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slavikrds [6]
3 years ago
6

Which of the following states that an orbital can obtain two electrons only if all other orbitals at that sublevel contain at le

ast one electron
Chemistry
1 answer:
Lesechka [4]3 years ago
7 0
Hunds rule states this
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Determine the pH of the following base solutions. (Assume that all solutions are at 25°C and the ion-product constant of water,
alexira [117]

Answer:

a) The pH of the solution is 12.13.

b) The pH of the solution is 12.17.

Explanation:

Ionic product of water =K_w=1.01\times 10^-{14}

K_w=[H^+][OH^-]

1.01\times 10^-{14}=[H^+][OH^-]

Taking negative logarithm on both sides:

-\log[1.01\times 10^-{14}]=(-\log [H^+])+(-\log [OH^-])

The pH is the negative logarithm of hydrogen ion concentration in solution.

The pOH is the negative logarithm of hydroxide ion concentration in solution.

13.99=pH+pOH

a) 1.39\times 10^{-2} M of NaOH.

Concentration of hydroxide ions:

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

So, [OH^-]=1\times [NaOH]=1\times 1.39\times 10^{-2} M=1.39\times 10^{-2} M

pOH=-\log[1.39\times 10^{-2} M]=1.86

13.99=pH+pOH

13.99=pH+1.86

pH=13.99-1.86=12.13

b) 0.0051 M of NaOH.

Concentration of hydroxide ions:

Al(OH)_3(aq)\rightarrow Al^{3+}(aq)+3OH^-(aq)

So, [OH^-]=3\times [Al(OH)_3]=3\times 0.0051 M=0.0153 M

pOH=-\log[0.0153 M]=1.82

13.99=pH+pOH

13.99=pH+1.82

pH=13.99-1.82=12.17

6 0
3 years ago
Anybody need a friend that is a girl? (not gf)
Simora [160]

Answer:

yesh

Explanation:

4 0
3 years ago
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What mass of calcium carbonate must be heated strongly to produce 1.12g of calcium oxide?
ra1l [238]
CaCO3=100g
CaO=56g
56g of CaO=100g of CaCO3
1.12g of CaO= 100/56*1.12 g of CaCO3
=2g of CaCO3 (ans)
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3 years ago
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Hydrogen is a special ,because it can act like two groups,____and_____
LuckyWell [14K]

Answer:

First and seventeenth group.

Explanation:

Hydrogen is a special case as it has only one electron in its outermost orbital.

The hydrogen can lose or can accept electron easily.

Thus it can form positive ion similar to alkali metals and negative ion similar to halogens.

Thus it can fall into two groups

a) I group [Alkali metals]

b) 17th Group [Halogens]

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Doy CORONITA a quien me ayude rapido que es un examen porfaaa
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Answer:

thank you for the points

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