Answer:
The new volume of the balloon is 600cm³
Explanation:
Given parameters:
Initial Volume, which is V₁ = 200cm³
Initial temperature, T₁ = 60°C
Final temperature T₂ = 180°C
Final Volume V₂ =?
To solve this kind of problem, we apply one of the gas laws that shows the relationship between volume and temperature.
This law is the Charles law, it states that " the volume of a fixed mass of a gas is directly proportional to its absolute temperature if pressure is constant".
It is simply expressed as:
V₁/T₁ = V₂/T₂
Since our unknown is V₂, we make it the subject of the expression given above:
V₂ = V₁T₂/T₁
Now input the corresponding values and solve:
V₂ = 200 x 180 / 60
V₂ = 36000/60
V₂ = 600cm³
The new volume of the balloon is 600cm³
For reaction
2 A + B ------------> 2 C
Rate = K [ A ]² [ B ]
<span> the order with respect to A is 2 and the order overall is 3.
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hope this helps!
Hello!
False.
The equation to calculate force, according to Newton's Second Law, is equivalent to F = m · a where:
m = mass of the object
a = acceleration of the object
Those two multiplied are equivalent to force.
Answer:
24.12 days
Explanation:
First off, let's find out how many decays the compound ; iodine131 undergoes to get to 17.5 percent of its original value.
Half life is simply the time required for a quantity to reduce to half of its initial value.
The half-life of iodine-131 is 8.04 days.
100% - 50% (First Half life)
50% - 25% (Second Half life)
25% - 17.5% (Third Half life)
This mwans i would take three halff lives;
Time requred = 3 * Half life = 3 * 8.04 days = 24.12 days
Answer:
c
Explanation:
A 0.85% saline solution would consist of <u>0.85 g NaCl made up to 100 mL of water.</u>
<em>A 0.85% saline solution contains 0.85% by weight of NaCl. Hence, in order to prepare such a solution, 0.85 g of NaCl is weighed out into a beaker or cylinder and distilled water is added up to the 100 mL mark. On the other hand, 8.5 g of the NaCl can be weighed out and then distilled water added to 1000 mL mark. </em>
The correct option is, therefore, c.