energy associate with position or shape
Answer:
Δ
= 84 Ω, = (40 ± 8) 10¹ Ω
Explanation:
The formula for parallel equivalent resistance is
1 / = ∑ 1 / Ri
In our case we use a resistance of each
R₁ = 500 ± 50 Ω
R₂ = 2000 ± 5%
This percentage equals
0.05 = ΔR₂ / R₂
ΔR₂ = 0.05 R₂
ΔR₂ = 0.05 2000 = 100 Ω
We write the resistance
R₂ = 2000 ± 100 Ω
We apply the initial formula
1 / = 1 / R₁ + 1 / R₂
1 / = 1/500 + 1/2000 = 0.0025
= 400 Ω
Let's look for the error (uncertainly) of Re
= R₁R₂ / (R₁ + R₂)
R’= R₁ + R₂
= R₁R₂ / R’
Let's look for the uncertainty of this equation
Δ / = ΔR₁ / R₁ + ΔR₂ / R₂ + ΔR’/ R’
The uncertainty of a sum is
ΔR’= ΔR₁ + ΔR₂
We substitute the values
Δ / 400 = 50/500 + 100/2000 + (50 +100) / (500 + 2000)
Δ / 400 = 0.1 + 0.05 + 0.06
Δ = 0.21 400
Δ = 84 Ω
Let's write the resistance value with the correct significant figures
= (40 ± 8) 10¹ Ω
The moon does not have its own light.
Analyzing the components and decay products of school lunches.
The index of refraction of the unknown material in which a ray of light is incident at 35° and refracted at 23° is 2.03
<h3>Snell's law</h3>
index of refraction (n) = Sine i / Sine r
n = Sine i / Sine r
Where
- i is the angle of incidence
- r is the angle of refraction
<h3>How to determine the refractive index </h3>
From the question given above, the following data were obtained:
- Index of refraction of oil (nₒ) = 1.38
- Angle of incidence (i) = 35°
- Angle of refraction (r) = 23°
- Index of refraction of unknown material (nᵣ) =?
nₒSine i = nᵣSine r
1.38 × Sine 35 = nᵣ × Sine 23
Divide both side by Sine 23
nᵣ = (1.38 × Sine 35) / Sine 23
nᵣ = 2.03
Thus, the index of refraction of the unknown material is 2.03
Learn more about Snell's law:
brainly.com/question/25758484
