2 years ago

Mechanical energy is a term that is used to describe

Physics

2 answers:

kolezko [41]2 years ago

5 0

Answer: B

both potential and kinetic

Rudiy272 years ago

3 0

Answer is B. both potential and kinetic energy.

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During what stage of engine operation does the piston move upward in the cylinder and force the burned gases out of the cylinder

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*l Take in air and fuel (Intake)
*l Compress (squeeze) the air and fuel (Compression)
*l Ignite and burn the air-and-fuel mixture (Power)
*l Get rid of the burned fuel gases (Exhaust)The Answer is C.Exhaust

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2 years ago

You want to estimate the diameter of a very small circular pinhole that you've made in a piece of aluminum foil. to do so, you s

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Central maximum = d* wavelength/ D
thus
12*10-^3 = 3.4*6.32*10-^7/D
D = 3.4*6.32*10-^7/12*10-^3
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2 years ago

A 60kg student traveling in a 1000kg car with a constant velocity has a kinetic energy of 1.2 x 10^4 J. What is the speedometer

777dan777 [17]

Answer:

17.64 km/h

Explanation:

mass of car, m = 1000 kg

Kinetic energy of car, K = 1.2 x 10^4 J

Let the speed of car is v.

Use the formula for kinetic energy.

$K = \frac{1}{2}mv^{2}$

By substituting the values

$1.2\times 10^{4} = \frac{1}{2}\times 1000\times v^{2}$

v = 4.9 m/s

Now convert metre per second into km / h

We know that

1 km = 1000 m

1 h = 3600 second

So, $v = \left (\frac{4.9}{1000} \right )\times \left ( \frac{3600}{1} \right )$

v = 17.64 km/h

Thus, the reading of speedometer is 17.64 km/h.

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2 years ago

Which of the following is a zone found in the open ocean

Svetlanka [38]

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2 years ago

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Bus starts from rest if the acceleration of the bus is 0.5 MS squared what will be the velocity at the end of two minutes and wh

Nutka1998 [239]

Explanation:

Given that,

Initial speed of the bus, u = 0

Acceleration of the bus, a = 0.5 m/s²

Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.

So,

$a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s$

Let d is the distance cover during that time. So,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m$

So, the final speed is 60 m/s and the distance covered during that time is 3600 m.

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2 years ago