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Rom4ik [11]
2 years ago
10

A light ray moving from oil (n=1.38) into an unknown material. If the light is incident at 35 and refracts at 23, what is the in

dex of refraction in the unknown material?
Physics
1 answer:
Nastasia [14]2 years ago
7 0

The index of refraction of the unknown material in which a ray of light is incident at 35° and refracted at 23° is 2.03

<h3>Snell's law</h3>

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

  • i is the angle of incidence
  • r is the angle of refraction
<h3>How to determine the refractive index </h3>

From the question given above, the following data were obtained:

  • Index of refraction of oil (nₒ) = 1.38
  • Angle of incidence (i) = 35°
  • Angle of refraction (r) = 23°
  • Index of refraction of unknown material (nᵣ) =?

nₒSine i = nᵣSine r

1.38 × Sine 35 = nᵣ × Sine 23

Divide both side by Sine 23

nᵣ = (1.38 × Sine 35) / Sine 23

nᵣ = 2.03

Thus, the index of refraction of the unknown material is 2.03

Learn more about Snell's law:

brainly.com/question/25758484

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podryga [215]

Answer:

<h2>0.39m/s^2</h2>

Explanation:

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