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Alina [70]
2 years ago
10

According to einstein's theory of simple relativity (_E + mc(2)_). BLANK is converted into BLANK.

Physics
1 answer:
True [87]2 years ago
8 0

Answer:

energy is converted into mass

Explanation:

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Mr. Powell, a white man who does not believe that racial discrimination is a
SCORPION-xisa [38]

Answer:

Modern racism

Explanation:

Modern racism emanates from an aggressive prejudicial behavior to a more subtle prejudicial behavior. This subtle prejudicial behavior advanced to a degree that is much more difficult to see, yet is regarded as more severe. The modern form of racism is the workplace. Although many companies promise an equal opportunity, there is little doubt that everyone is treated equally within their place of work. Subtle, modern racism is believed to create an image that seems more politically correct. The politically correct way to discriminate is through a "polite" form of racism. In the past racism was easily defined and institutional

Modern racism is among the most widespread forms of verbally expressed negative racial attitudes in the United States .

3 0
3 years ago
A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of valu
ehidna [41]

Answer:5.21 N

Explanation:

Given

B=5.210 T

I=2 A

L=0.5 m

Given Wire is perpendicular to Magnetic field

\theta =90^{\circ}

F=IL\times B

F=BIL sin\theta

F=5.210\cdot 2\cdot 0.5 sin(90)

F=5.210 N

as  1 Tesla =1 N/A/m

4 0
3 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
leonid [27]

Answer:

KE_A=33\ J

KE_B=99\ J

Explanation:

Given:

Let mass of the particle B be, m_B=m

then the mass of particle A, m_A=3m

Energy stored in the compressed spring, E=132\ J

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132

3m.v_A^2+m.v_B^2=264 .............................(1)

<u>Using the conservation of linear momentum:</u>

m_A.v_A+m_B.v_B=0

3m.v_A+m.v_B=0 .............................(2)

Put the value of v_A from eq. (2) into eq. (1)

3m\times (\frac{-v_B}{3})^2+m.v_B^2=264

v_B^2=\frac{198}{m}  ...........................(3)

<u>Now the kinetic energy of particle B:</u>

KE_B=\frac{1}{2}\times m_B\times v_B^2

KE_B=\frac{1}{2}\times m\times \frac{198}{m}

KE_B=99\ J

Put the value of v_B^2 form eq. (3) into eq. (1):

v_A^2=\frac{22}{m}

<u>Now the kinetic energy of particle A:</u>

<u />KE_A=\frac{1}{2}m_A.v_A^2<u />

<u />KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}<u />

KE_A=33\ J

6 0
3 years ago
Compute the ratio of the rate of heat loss through a single-pane window with area 0.15 m2 to that for a double-pane window with
Rudik [331]

Answer:

2.80321285141

Explanation:

L_g = Thickness of glass = 4.5 mm

k_g = Thermal conductivity of glass = 0.8 W/mK

R_0 = Combined thermal resistance = 0.15\times m^2K/W

L_a = Thickness of air = 6.6 mm

k_a = Thermal conductivity of air = 0.024 W/mK

The required ratio is the inverse of total thermal resistance

\dfrac{2(L_g/k_g)+R_0+(L_a/k_a)}{(L_g/k_g)+R_0}\\ =\dfrac{2(4.5\times 10^{-3}/0.8)+0.15+(6.6\times 10^{-3}/0.024)}{(4.5\times 10^{-3}/0.8)+0.15}\\ =2.80321285141

The ratio is 2.80321285141

4 0
3 years ago
Read 2 more answers
A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex
Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

\text{Efficiency of the heat engine} = \eta = 26\% = 0.26

\text{Energy taken in by the heat engine during each cycle} = Q_h

\text{Energy exhausted by the heat engine in each cycle} = Q_c = 8.55*10^3 J

\eta = 1 - \frac{Q_{c}}{Q_{h}}

0.26 = 1 - \frac{8.55\ast 10^{3}}{Q_{h}}

\frac{8.55* 10^{3}}{Q_{h}} = 0.74

Q_h = \frac{8.55*10^3}{0.74}

Q_h = 11.554*10^3J

PART A)

Work done by the heat engine in each cycle = W

W = Q_h-Q_c

W = 11.554*10^3J-8.55*10^3J

W = 3004J

According to the value given we have that,

P = 4.0kW

P = 4000W

Power is defined as the variation of energy as a function of time therefore,

P = \frac{W}{t}

4000W = \frac{3004J}{t}

t = \frac{3004}{4000}

t = 0.75s

Therefore the interval for each cycle is 0.75s

5 0
3 years ago
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