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mel-nik [20]
3 years ago
9

How many molecules are there in 13.5g of lithium oxide?please help! ​

Chemistry
2 answers:
forsale [732]3 years ago
8 0
I looked it up and got 0.45178606089406353 as the exact number
i used an online converter
nirvana33 [79]3 years ago
6 0

Answer:

the answer is 29.8814

Explanation:

because this is the answer to your question

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Why do we use a double arrow in the dissociation equation for a weak acid answer?
Zepler [3.9K]
Answer is: because weak acids do not dissociate completely.

The strength of an Arrhenius acid determines percentage of ionization of acid and the number of H⁺ ions formed. <span>
Strong acids completely ionize in water and give large amount ofhydrogen ions (H</span>⁺), so we use only one arrow, because reaction goes in one direction and there no molecules of acid in solution.

For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).

<span> Weak acid partially ionize in water and give only a few hydrogen ions (H</span>⁺), in the solution there molecules of acid and ions.

For example cyanide acid: HCN(aq) ⇄ H⁺(aq) + CN⁻(aq).


4 0
3 years ago
What is the situation when I might travel high velocity but low acceleration
Anna007 [38]
Cruising at 35,000 feet in an airliner, straight toward the east, 
at 500 miles per hour.  

Since your speed is not changing and you're moving in a straight line,
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6 0
3 years ago
NO ONE ANSWERS MY QUESTIONS
leva [86]

Answer:

where is the answer options because it sounds like I need some

3 0
2 years ago
Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]
ziro4ka [17]

Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

(3) H(C6H5+)SO3− + HSO4− → C6H5SO3− + H2SO4

[fast]

(4) C6H5SO3− + H3O+ → C6H5SO3H + H2O

[fast]

write the overall rate law for the initial rate of the reaction as a fraction.

Rate=k(________/_________)

Answer:

The overall rate law for the initial reaction is = k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

                        rate = k_{2} [SO_{3}][C_{6}H_{6}]

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

                       rate = k_{1}[H_{2}SO_{4}]^{2}

Hence when we substitute equation 2 in equation one,

                   Rate comes out to be =  k_{overall} [H_{2}SO_{4}]^{2} [C_{6}H_{6}]

6 0
3 years ago
What is the purpose of the catalyst?
Hitman42 [59]
Its C

a catalyst speeds up a reaction by offering the reaction an alternative reaction pathway with a lower activation energy 

hope that helps 
5 0
2 years ago
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