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Arturiano [62]
4 years ago
5

What is one of the by products of using a cooling system?

Chemistry
1 answer:
nasty-shy [4]4 years ago
3 0

Answer:

air conditioning

Explanation:

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0.000000655 mL in scientific notation
alina1380 [7]

Answer:

<u>The answer is 6.55 * 10⁻⁷</u>

Explanation:

Let's write 0.000000655 mL in scientific notation:

The first step is you have to move the decimal place until you have a number between 1 and 10. If you keep moving the decimal point to the right in 0.000000655 you will get 6.55.

Now, the second step is you count how many places you moved the decimal point. You moved it 7 places to the right to change 0.000000655 to 6.55.

Finally, You need to show that you moved the decimal point 7 places to the right by noting that the number should be multiplied by 10⁻⁷ because a power of ten with a negative exponent, such as 10⁻⁷, means the decimal was moved to the right.

<u>The answer is 6.55 * 10⁻⁷</u>

3 0
4 years ago
What is chemistry? ​
Shkiper50 [21]

Answer: chemistry is love ❤️ #bae

Explanation: ok just kidding. The dictionary says chemistry is the scientific discipline with elements and compounds of atoms, molecules, and ions

6 0
3 years ago
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The cycling of carbon between the living and non-living parts of the Earth system is an important result of which of the followi
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Answer:

b. Plants and animals exchanging gases with the atmosphere

Explanation:

5 0
3 years ago
A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva
maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of HNO_3

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of C_6H_5NH_2.

M_2\text{ and }V_2 are the final molarity and volume of HNO_3.

We are given:

M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?

Putting values in above equation, we get:

0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of C_6H_5NH_2 +  Volume of HNO_3

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M

Now we have to calculate the pH of the solution.

At equivalence point,

pOH=\frac{1}{2}[pK_w+pK_b+\log C]

pOH=\frac{1}{2}[14+4.87+\log (0.0437)]

pOH=8.76

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24

Thus, the pH of the solution is, 5.24

4 0
4 years ago
Who was on the grand committee
Rzqust [24]

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European Union was on grand committee

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