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tatyana61 [14]
3 years ago
9

Solve the system of equations. Y=9x-17 y = x + 23

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

y=9x-17; x=17/9 or x=1 8/9 or x=1.8

y=x+23; x= -23

Step-by-step explanation:

y=9x-17

0=9x-17 (Move variables to the left-hand side and change its sign)

-9x=-17 (Divide both sides of the equation by -9)

x=17/9, x=1 8/9, or x=1.8

y=x+23

0=x+23 (To find x-intercept/zero, substitute y=0)

-x=23 (Move variable to the left-hand side and change its sign)

x= -23 (Change the signs on both sides of the equation)

x= -23

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John ordered five large size pizzas for a party. Five kids each ate 1/10 slice, and twelve adults each at 3/10 slices.
astraxan [27]

Answer:

a) 4 1/10 slices eaten

b) cannot be solved because we don't know how many slices in each pizza

Step-by-step explanation:

5*1/10=5/10

12*3/10=36/10

36/10+5/10=41/10

41/10=4 1/10 slices

8 0
3 years ago
4a + (–6b) – 3a + 2b factor the expression
Gemiola [76]

Answer:

a−4b

Step-by-step explanation:

Combine Like Terms:

=4a+−6b+−3a+2b

=(4a+−3a)+(−6b+2b)

=a+−4b

have a great day

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3 years ago
Nine and one-half less than four and one-half times a number is greater than 62.5. Which of the following represents the solutio
kolbaska11 [484]
4.5x - 9.5 > 62.5
4.5x > 62.5 + 9.5
4.5x > 72
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4 0
3 years ago
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Nikolas calculated the volume of the prism. His work is shown below. A triangular prism. The triangular base has a base of 5.8 f
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Answer:

B he used the incorrect formula for the volume of the prism

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Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
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