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Paul [167]
4 years ago
6

HELP ASAP PLEASE!!!

Physics
2 answers:
Sati [7]4 years ago
8 0

Answer:

A. it would be a very small earthquake

Explanation:

shtirl [24]4 years ago
6 0
A. a very small earthquakes
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PLZZZZZZ HELP
sveticcg [70]

Answer:

A television

Explanation:

When you plug in a device such as a TV set into a wall socket, the electricity used is alternating current.

6 0
3 years ago
Read 2 more answers
In a double‑slit interference experiment, the wavelength is lambda=487 nm , the slit separation is d=0.200 mm , and the screen i
pantera1 [17]

Answer:

Δx = 4.68 x 10⁻³ m = 4.68 mm

Explanation:

The distance between the consecutive maxima, in Young's Double Slit Experiment is given bu the following formula:

Δx = λD/d

So, the distance between the eighth order maximum and the fourth order maximum on the screen will be given as:

Δx = 4λD/d

where,

Δx = distance between eighth order maximum and fourth order maximum=?

λ = wavelength = 487 nm = 4.87 x 10⁻⁷ m

d = slit separation = 0.2 mm = 2 x 10⁻⁴ m

D = Distance between slits and screen = 48 cm = 0.48 m

Therefore,

Δx = (4)(4.87 x 10⁻⁷ m)(0.48 m)/(2 x 10⁻⁴ m)

<u>Δx = 4.68 x 10⁻³ m = 4.68 mm</u>

5 0
3 years ago
A 15 A current is directed along the positive x-axis and perpendicular to a uniform magnetic field. The conductor experiences a
fenix001 [56]

Answer:

The magnitude of magnetic field in the region through the current passes is 0.0133 T

Explanation:

Given:

Current I = 15 A

Force per unit length \frac{F}{l} = 0.20 \frac{N}{m}

The magnetic force on current carrying conductor is given by,

   F = IlB

For finding the magnetic field,

   B = \frac{F}{Il}

   B = \frac{0.20}{15}

   B = 0.0133 T

Therefore, the magnitude of magnetic field in the region through the current passes is 0.0133 T

6 0
3 years ago
What is the relationship between the normal force and weight
GalinKa [24]

Answer: they have the same magnitude.

Explanation:

normal force = mg

weight = mg

4 0
3 years ago
Vision. When light having vibrations with angular frequency ranging from 2.7×1015rad/s to 4.7×1015rad/s strikes the retina of th
Amiraneli [1.4K]

Answer:

Explanation:

Given

angular frequency ranging From 2.7\times 10^{15}\ rad/s\ to\ 4.7\times 10^{15}\ rad/s

we know \omega =2\pi f

where f=frequency

\omega =angular\ Frequency

for \omega =2.7\times 10^{15}

f=\frac{2.7\times 10^{15}}{2\pi }

f=4.29\times 10^{14} Hz

for \omega =4.7\times 10^{15}

f=\frac{4.7\times 10^{15}}{2\pi }

f=7.47\times 10^{14} Hz

Frequency ranges from  4.29\times 10^{14}\ Hz\ to\ 7.47\times 10^{14} Hz          

6 0
3 years ago
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