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3 years ago

What is the relationship between the normal force and weight

Physics

1 answer:

GalinKa [24]3 years ago

4 0

Answer: they have the same magnitude.

Explanation:

normal force = mg

weight = mg

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A visitor to a lighthouse wishes to determine the height of the tower. She ties a spool of thread to a small rock to make a simp

masha68 [24]

To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

$T = 2\pi \sqrt{\frac{l}{g}}$

Where

l = Length

g = Gravity

Re-arrange to find L,

$L = g (\frac{T}{2\pi})^2$

Our values are given as

$g = 9.81m/s$

$T = 10.1s$

Replacing,

$L = g (\frac{T}{2\pi})^2$

$L = (9.81) (\frac{10.1}{2\pi})^2$

$L = 25.348m$

Therefore the height would be 25.348m

5 0

3 years ago

Determine the magnitude of the force between two 42 m-long parallel wires separated by 0.03 m, both carrying 6.3 A in the same d

xz_007 [3.2K]

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

length of the two parallel wires, L = 42 m

distance between the two wires, r = 0.03 m

current in both wires, I₁, I₂ = 6.3 A

Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

$F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F = 0.0111 \ N$

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

6 0

3 years ago

Use the information and diagram to answer the following question.

Mumz [18]

Answer:b

Explanation:

Because I don’t know

8 0

3 years ago

The Moon is much smaller than Earth but is still made of rock that you could walk on. However, you would need a spacesuit to do

weqwewe [10]

Because there is no oxygen in space and we need oxygen to function so we need the suit to incapsulate us in oxygen so we can respire and so can our skin

4 0

2 years ago

A proton travels with a speed of 5.02×10⁶ m/s in a direction that makes an angle of 60.0° with the direction of a magnetic ficld

lesantik [10]

Answer: The magnitude of the proton's acceleration is 0.748 ×10^14 m/s²

Explanation:
the velocity ,v, of ththe proton = 5.02×10^6 m/s
Magnitude , B , of the magnetic field = 0.180 T

First , we need to find the magnitude of the Force on the proton. This is given by the relation :
F = q(v x B) = qvBsinθ

where 'q' is the charge of proton , q= 1.6×10^-19 C
θ is the angle the proton makes with the direction of the magnetic field

Putting the respective values of v, B ,θ in the above equation, we get:

F = (1.6×10^-19 C)(5.02×10^6 m/s)(0.180T) sin60°
∴ F = 1.25 ×10^-13 N

Now , from Newton's second law we know that ,
F=m×a

∴ a = F/m

Mass of a proton = 1.67×10^27 kg
a= 1.25 × 10^-13 N / 1.67 × 10^27 kg

a= 0.748 × 10^14 m/s² =acceleration of the proton

(To know more about Magnetic Fields : brainly.com/question/9095546)

5 0

2 years ago