What is the relationship between the normal force and weight

True or False if something was turn to make something is it a chemical reaction

sesenic [268]

If something was turned? I'm not really sure what you are talking about, but for something to become a chemical reaction it involves and arrangement of molecular and ionic structure of a substance, as opposed to a change in physical form or a nuclear reaction.

8 0

3 years ago

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A piston-cylinder arrangement contains air modeled as an ideal gas with constant specific heat ration of k =1.4. The air undergo

loris [4]

Answer:

Pish posh idk xD im busy but ill help in a second

Explanation:

4 0

3 years ago

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

Alja [10]

Answer:

Part a)

$M = 7.25 \times 10^{25} kg$

Part b)

$M = 2\times 10^{30} kg$

Explanation:

Part a)

As we know that the diameter of the planet is given as

$d = 1.8 \times 10^7 m$

now the radius of the planet is given as

$r = 9 \times 10^6 m$

now we know that the acceleration due to gravity of the planet is given by the equation

$g = \frac{GM}{r^2}$

here we know that

$g = 59.7 m/s^2$

now from above equation we have

$59.7 = \frac{(6.67 \times 10^{-11})M}{(9\times 10^6)^2}$

now we have

$M = 7.25 \times 10^{25} kg$

Part b)

Now by kepler's law we know that

time period of revolution of planet about the star is given as

$T = 2\pi \sqrt{\frac{r^3}{GM}}$

so we have

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

now we have

$\frac{1^2}{402^2} = \frac{(1.5 \times 10^11)^3}{r^3}}$

$rr = 8.17 \times 10^{12} m$

mula of time period

$402\times (365\times 24 \times 3600) = 2\pi \sqrt{\frac{(8.17\times 10^12)^3}{(6.67\times 10^{-11})M}}$

Now we have

$M = 2\times 10^{30} kg$

7 0

3 years ago

Where do magnetic fields occur?

Tresset [83]

Answer:

<h2>The Magnetosphere and Magnets</h2>

Explanation:

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According to the <em>National Geographic, </em><em>"Earth’s magnetic field dominates a region called the magnetosphere, which wraps around the planet and its atmosphere. Solar wind, charged particles from the sun, presses the magnetosphere against the Earth on the side facing the sun and stretches it into a teardrop shape on the shadow side. The magnetosphere protects the Earth from most of the particles, but some leak through it and become trapped. When particles from the solar wind hit atoms of gas in the upper atmosphere around the geomagnetic poles, they produce light displays called auroras. These auroras appear over places like Alaska, Canada and Scandinavia, where they are sometimes called “Northern Lights.” The “Southern Lights” can be seen in Antarctica and New Zealand. The magnetic field is the area around a magnet that has magnetic force. All magnets have north and south poles."</em>

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<em>Hope this helps! <3</em>

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5 0

3 years ago

A wheel rotates through an angle of 15.6 rad as it slows down uniformly from 22.0 rad/s to 13.5 rad/s. What is the magnitude of

charle [14.2K]

Answer:

α = -9.67 rad/s²

Explanation:

the magnitude of the angular acceleration of the wheel can be calculated using the expression below;

ω² = ω₀² + 2α(θ- θ₀)..............eqn(1)

ω² = ω₀² + 2αΔθ...............eqn(2)

Δθ= θ- θ₀= 15.6 rad

ω = 13.5 rad/s

ω₀ = 22.0 rad/s

where ω₀= initial angular velocity

ω= final angular velocity

We can now input all the parameters into the equation(2) above

(13.5)² = (22.0)² + 2αΔθ

2αΔθ= (13.5)² - (22.0)²

2αΔθ= 182.25 - 484

2αΔθ=301.75

But our Δθ= 15.6 rad

2α *15.6 rad = 301.75

2α=301.75/15.6

2α=19.343

α=9.67

the magnitude of the angular acceleration of the wheel is 9.67 rad/s²

7 0

3 years ago