To answer the question, we assume that the given compound is an ideal gas that at STP, one mole of the substance will occupy 22.4 L. From the given volume, we determine the number of moles of substance.
7.8 L / (22.4 L /mole) = 0.3482 moles of cfa
Then, we multiply this number of moles by the molar weight of cfa which is equal to 88 g/mol.
Multiplying,
weight = (0.3482 moles of cfa) x (88 g/mol) = <em>30.64 grams</em>
Answer:
A. 1:1
Explanation:
The ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the sodium and bromine compound is 1:1 because sodium needs to lose one electron and bromine needs one electron to become stable and complete its outermost shell. When sodium lose electron, it become cation and gain +1 charge while on the other hand, the bromine accept one electron and become anion and gain -1 charge so that's why we can say that there is 1:1 of metal cationic (+) atom to nonmetal anionic (-) atom in the sodium and bromine compound.
Answer:
The outermost shell holds the so called valence electrons, therefore we have 8 electrons in that shell...
2s have 2 electrons and 2p hold 6 electrons 6+2=8
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Explanation: