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tigry1 [53]
3 years ago
11

Write the net ionic equation (including phases) that corresponds to zn(no3)2 na2co3 znco3 2nano3

Chemistry
2 answers:
Dmitriy789 [7]3 years ago
7 0
Zn(no3)2  +  NaCO3  ---->  ZnCO3  +   2NaNO3

Zn^2+(aq)   +  2 NO3^-(aq)  +  2Na^+(aq)  +  CO3^2(aq)- --->  ZnCO3(s)  +  2Na^+(aq)    +  2NO3^-(aq)

we  cancel  the  the  spectator  in   both  side  in  this   case  is   Na^+    and  NO3-
this  yield
Zn^2+(aq)   +  CO^-2(aq)  -----ZnCO3(s)
Elza [17]3 years ago
5 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of zinc nitrate and sodium carbonate is given as:

Zn(NO_3)_2(aq.)+Na_2CO_3(aq.)\rightarrow ZnCO_3(s)+2NaNO_3(aq.)

Ionic form of the above equation follows:

Zn^{2+}(aq.)+2NO_3^-(aq.)+2Na^+(aq.)+CO_3^{2-}(aq.)\rightarrow ZnCO_3(s)+2Na^+(aq.)+2NO_3^-(aq.)

As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Zn^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow ZnCO_3(s)

Hence, the net ionic equation is written above.

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