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3 years ago

Write the formula sodium ion

Chemistry

2 answers:

Effectus [21]3 years ago

6 0

Answer:

NA+

Explanation:

NA+

hope help

it's NA+

finlep [7]3 years ago

6 0

Write the formula of sodium ion.

$\implies {\blue {\boxed {\boxed {\purple {\sf { {Na}^{ + } }}}}}}$

$\bold{ \green{ \star{ \orange{Mystique35}}}}⋆$

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Marijuana most abundant psychoactive chemical is delta-9- tetrahydrocannabinol or

Galina-37 [17]

<h2>Answer:</h2>

<u>Yes the statement is</u><u> True</u>

<h2>Explanation:</h2>

THC is a chemical which stands for delta-9-tetrahydrocannibinol or Δ-9-tetrahydrocannabinol (Δ-9-THC). This chemical is a cannabinoid molecule in marijuana or cannabis that has long been known as the main psychoactive ingredient in marijuana which means that it is the substance that causes users to experience the marijuana high. It can be detected in the blood up to 20 hours after ingestion, and it's stored in the body fat and organs for three to four weeks after ingestion.

7 0

3 years ago

Read 2 more answers

A 2.00-mol sample of hydrogen gas is heated at constant pressure from 294 K to 414 K. (a) Calculate the energy transferred to th

Furkat [3]

Answer:

a) The energy transferred is 6.91 kJ

b) The internal energy is 4.90 kJ

c) The work done on the gas is - 2.01 kJ

Explanation:

Step 1: Data given

Number of moles of hydrogen gas = 2.00 moles

Pressure = constant

Temperature is heated from 294 K to 414 K

Molar heat capacity of hydrogen gas = 28.8 J/mol*K

Step 2: Calculate the energy transferred to the gas by heat.

Q = n* Cp * ΔT

⇒with Q =the energy transferred

⇒with n = the number of moles = 2.00 moles

⇒with Cp = the Molar heat capacity of hydrogen gas = 28.8 J/mol*K

⇒ with ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

Q = 2.00 * 28.8 * 120

Q = 6912 J = 6.91 kJ

Step 3: Calculate the increase in its internal energy.

ΔEint = n*Cv*ΔT

⇒with ΔEint = the increase in its internal energy.

⇒with n = the number of moles = 2.00 moles

⇒with Cv = The constant volume = 20.4 J/mol*K

⇒with ΔT = Temperature 2 - Temperature 1 = 414 - 294 = 120K

ΔEint = 2.00 * 20.4 * 120

ΔEint =4896 J = 4.90 kJ

Step 4: Calculate the work done on the gas.

Work done on the gas = -Q + ΔEint

W = -6.91 kJ + 4.90 kJ

W = -2.01 kJ

6 0

3 years ago

Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?

sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

$density=\frac{mass}{volume}$

Now, density of isooctane = $0.692 g/mL$

Volume = $3.8 gal$

Since, 1 gallon = 3.78 L

So, 3.8 gal = $3.78 L\times 3.8$

= $14.364 L$

As, 1 L = 1000 mL

Therefore, $14.364 L$ = $14.364 L\times 1000 mL$

Volume in mL = $14364 mL$

Put the values,

$0.692 g/mL=\frac{mass}{14364 mL}$

$m = 0.692 g/mL\times 14364 mL$

= $9939.888 g$

Hence, mass of 3.8 gal of the gasoline is $9939.888 g$ .

6 0

3 years ago

BJECTIVE TYPE QUESTIONS

8090 [49]

Answer:

1.Physical change

2. Chemical change

3. Heat

4.photosynthesis

5. composition

4 0

2 years ago

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago

Write the formula sodium ion​

Write the formula sodium ion