1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeyben [28]
3 years ago
13

A(n) 1400-kg car going at 6.32 m/s in the positive x direction collides with a 2900-kg truck at rest. The collision is totally i

nelastic and takes place over an interval of 0.203 s. Assume that no brakes are applied during the collision and the car strikes the rear of the truck. Neglect the friction between the vehicles and the ground.
What is the average x component of the acceleration of the car during the collision?
What is the average x component of the acceleration of the truck during the collision?
Physics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

a) Acceleration of the car is given as

a_{car} = -21 m/s^2

b) Acceleration of the truck is given as

a_{truck} = 10.15 m/s^2

Explanation:

As we know that there is no external force in the direction of motion of truck and car

So here we can say that the momentum of the system before and after collision must be conserved

So here we will have

m_1v_1 + m_2v_2 = (m_1 + m_2)v

now we have

1400 (6.32) + 2900(0) = (1400 + 2900) v

v = 2.06 m/s

a) For acceleration of car we know that it is rate of change in velocity of car

so we have

a_{car} = \frac{v_f - v_i}{t}

a_{car} = \frac{2.06 - 6.32}{0.203}

a_{car} = -21 m/s^2

b) For acceleration of truck we will find the rate of change in velocity of the truck

so we have

a_{truck} = \frac{v_f - v_i}{t}

a_{truck} = \frac{2.06 - 0}{0.203}

a_{truck} = 10.15 m/s^2

You might be interested in
The overhang beam is subjected to the uniform distributed load having an intensity of w = 50 kn/m. determine the maximum shear s
alex41 [277]
Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

We need to determine the maximum shear stress developed in the beam:

τ = F/A

Assuming the area of the beam is 100 m^2 with a length of 10 m.

τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
τ = 5000 N/ m^2<span />
8 0
3 years ago
An ambulance is traveling north at 55.9 m/s, approaching a car that is also traveling north at 28.4 m/s. The ambulance driver he
wlad13 [49]

Answer:

915 Hz

Explanation:

The observed frequency from a sound source is given as

f₀ = f [(v + v₀)/(v+vₛ)]

where

f₀ = observed frequency of the sound by the observer = ?

f = actual frequency of the sound wave = 983 Hz

v = actual velocity of the sound waves = 343 m/s

vₛ = velocity of the source of the sound waves = 55.9 m/s

v₀ = velocity of the observer = 28.4 m/s

f₀ = 983 [(343+28.4)/(343+55.9)]

f₀ = 915.2 Hz = 915 Hz

6 0
3 years ago
3. A ball is thrown straight up with an initial velocity of 40 m/s.
grandymaker [24]

Answer:

The velocity at the top of its path will be zero (0)

Explanation:

We can solve this problem or particular situation using the principle of energy conservation.

Which tells us that energy is transformed from kinetic energy to potential energy and vice versa. A reference point should be considered at which the potential energy is zero, and at this point the initial velocity of 40 [m/s] is printed to the ball.

Ek=Ep\\where:\\Ek=kinetic energy [J]\\Ep=potencial energy [J]

The potential energy is determined by:

Ep=m*g*h\\where:\\m=mass of the ball[kg}\\g=gravity[m/s^2]\\h=heigth [m]\\

The kinetic energy is determined by:

Ek=\frac{1}{2}*m*v_{0} ^{2}  \\where\\v_{0} = initial velocity[m/s]

Ek=Ep\\\frac{1}{2} *m*v_{0} ^{2} =m*9.81*h\\h=\frac{40^{2}}{2*9.81} \\h=81.5[m]

This will be the maximum path but, its velocity at this point will be zero. Because now all the kinetic energy has been transformed in potential energy.

8 0
3 years ago
Suppose mass and radius of the planet are half and twice that of earth's respectively. If acceleration due to gravity of the ear
stich3 [128]

Answer:

The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

Explanation:

Given that,

Mass of the planet, m = 1/2M

Radius of the planet, r = 2R

Where M and R is the mass and radius of the Earth respectively.

The acceleration due to gravity of Earth, g = 10 m/s²

The acceleration due to gravity of Earth is given by the relation,

                                       g = GM/R²

Similarly, the acceleration due to gravity of that planet is

                                        gₐ = Gm/r²

where G is the Universal gravitational constant

On substituting the values in the above equation

                                        gₐ = G (1/2 M)/4 R²

                                             = GM/8R²

                                             = 1/8 ( 10 m/s²)

                                             = 1.25 m/s²

Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

3 0
3 years ago
The potential energy of a 40-kg cannonball is 14000 J. How high was the cannon ball to have this much potential energy?
Arturiano [62]

Answer:

35.71 m

Explanation:

Potential energy is calculated using this formula:

  • PE = mgh
  • where m = mass (kg). g = gravitational acceleration on Earth (9.8 m/s²), h = height (m)

We are given 3 out of the 4 variables in this problem. We want to solve for h, the height of the cannon ball.

List out the known variables:

  • PE = 14,000 J
  • m = 40 kg
  • g = 9.8 m/s²
  • h = ? m

Substitute these values into the potential energy formula.

  • 14,000 = (40)(9.8)h
  • 14,000 = -392h
  • h = 35.7142857143

The cannonball was 35.71 m high to have a potential energy of 14,000 J.

4 0
3 years ago
Other questions:
  • A truck slows down. Which claim about the forces acting on the truck must be true? Choose 1 answer: Choose 1 answer: (Choice A)
    6·1 answer
  • Help please 80pnts and brainliest guaranteed
    7·1 answer
  • You are standing 1 meter from a squawking parrot. If you move to a distance three meters away, the sound
    12·2 answers
  • Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes th
    7·1 answer
  • A rectangular plate has a length of (22.4 ± 0.2) cm and a width of (8.4 ± 0.1) cm. Calculate the area of the plate, including it
    10·1 answer
  • Which of the following equals the change in velocity divided by the time?
    14·2 answers
  • I kinda don’t know how to solve this I need help.
    15·1 answer
  • 21. A 1000-kg automobile moving with a speed of 24 m/s relative to the road collides with a 500-kg automobile initially at rest.
    15·1 answer
  • QC Suppose you hear a clap of thunder 16.2s after seeing the associated lightning strike. The speed of light in air is 3.00× 10⁸
    6·1 answer
  • Determine the magnitude of the momentum of a ... 107-kg halfback moving eastward at 8 m/s.The halfback's momentum in kgm/s is:
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!