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Aloiza [94]
3 years ago
10

Atmospheric conditions near a mountain range are such that a cloud at an altitude of 2.00 km contains 3.20 ✕ 10^7 kg of water va

por. How long (in years) would it take for a 2.96 kW pump to raise this amount of water (at a constant speed) from Earth's surface to the altitude of the cloud?
Physics
1 answer:
kykrilka [37]3 years ago
3 0

Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

height h = 2.00 km = 2 × 10^3 m

power p = 2.96 kW  =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power =  mass  gravity force × height / time

now put all value and find time period

power =  mass × gravity force × height / time

2.96 × 10^3 =  3.20 ✕ 10^7  × 9.81× 2 × 10^3  / time

time =  62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

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<h3>What is the eye's near-point distance?</h3>

The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.

The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:

1/f = 1/v + 1/u

where;

f = focal length

v = image distance

u = object distance

From the data provided;

f = 2.20 cm

v = 2.75 cm

u = ?

Solving for u:

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In conclusion, the lens formula is used to determine the eye's near-point distance.

Learn more about eye's near-point distance at: brainly.com/question/16391605

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Answer:

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w = work done by the system = -300J

Explanation:

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