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Maksim231197 [3]

3 years ago

6

There are 150 calories in a cup of whole milk and only 80 in a cup of skim milk. In switching to skim milk, find the percent dec

rease in number of calories.
The percent decrease is %. (Round to the nearest tenth if needed.)

1 answer:

ss7ja [257]3 years ago

5 0

Answer:

53.3%

Step-by-step explanation:

80/150=160/300

160/300=53.33/100

The decrease in calories is 53.3%

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Mr. quick bought new computer system. The regular price was 1,580 , but he got a 15% discount. How much did he actually pay?

N76 [4]

Answer:

$1343

Step-by-step explanation:

The equation would be

x= 1580 (1-0.15)

x represents how much he actually pays.

1-0.15=0.85.

1580×0.85=1343

8 0

2 years ago

5TH GRADE MATH! HELP! What is written in standard form? A. 0.8 B. 0.871 C. 871 D. 8,710

vladimir1956 [14]

Answer:B

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$

$C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35$

$C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21$

$C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1$

For all the calculations just recall that 4! =24 and 5!=120.

6 0

2 years ago

PLZZZZZ HELP ME Find the sum

mario62 [17]

Answer:

$27 \frac{2}{3}$

Step-by-step explanation:

Ok, so first substitute x for 4 in

"g(x) = 5x + 1", and x for 3 in

"k(x) = 2/x + 2x". Now you got:

g(4) = 5(4) + 1

k(3) = 2/(3) + 2(3)

Now you can solve each individually.

g(4) = 5 × 4 = 20

20 + 1 = 21

g(4) = 21

k(3) = 2 × 3 = 6

6 + 2/3 = 6 2/3

k(3) = 6 2/3

g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>

Hope this helps :)

7 0

2 years ago

I need help with this in math right now I'm struggling

kaheart [24]

Answer:

y=-4x-2

Step-by-step explanation:

linear function, y = mx+c

the y intercept of the graph,c, is -2

thus y = mx - 2

substitute a point on the graph into the equation, (2,-1)

2 = m(-1) -2

m = - 4

thus equation of graph is y = -4x-2

3 0

2 years ago