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Ulleksa [173]
2 years ago
5

Energy is the ability to do.

Physics
2 answers:
pogonyaev2 years ago
7 0
Energy is the ability to do work
Aleks04 [339]2 years ago
6 0
Energy is the ability to do work
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A rectangular field is to be enclosed on four sides with a fence. Fencing costs $2 per foot for two opposite sides, and $3 per f
borishaifa [10]
<h2>Dimension for cheap enclose = 32.45 ft x 23.52 ft</h2>

Explanation:

Area of rectangular field, A = 830 ft²

Length = l

Width = w

So we have

                 l x w = 830

                    l=\frac{830}{w}

Fencing costs $2 per foot for two opposite sides, and $3 per foot for the other two sides.

            Cost for fencing, C = 2 x 2 x w + 3 x 2 x l = 4 w + 6 l

             C=4w+6\times \frac{830}{w}

For minimum cost we have derivative is zero

           dC=4\times dw-6\times \frac{830}{w^2}\times dw\\\\0=4\times dw-6\times \frac{830}{w^2}\times dw\\\\w^2=1245\\\\w=32.45ft\\\\lw=830\\\\l\times 32.45=830\\\\l=23.52ft

Dimension for cheap enclose = 32.45 ft x 23.52 ft

8 0
2 years ago
In tenis does your knees have to be slightly flexed for both the forehand and backhand?
Elena L [17]

Answer:

yes

Explanation:

8 0
2 years ago
You throw a rock straight up into the air with a speed of 14.2 m/s. how long does it take the rock to reach its highest point?
slega [8]

The acceleration of gravity on or near the Earth's surface is 9.8 m/s² downward.
Is that right ?           I don't hear any objection, so I'll assume that it is.

That means that during every second that gravity is the only force on an object,
the object either gains 9.8m/s of downward speed, or it loses 9.8m/s of upward
speed.   (The same thing.)

If the rock starts out going up at 14.2 m/s, and loses 9.8 m/s of upward speed
every second, it runs out of upward gas in (14.2/9.8) = <em>1.449 seconds</em> (rounded)

At that point, since it has no more upward speed, it can't go any higher.  Right ?

(crickets . . .)

4 0
3 years ago
1. A stationary 50 tonne submarine fires a missile of mass 40kg at
White raven [17]

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne=50\times 1000=50000kg

Mass of the missile m=40  kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s

8 0
3 years ago
Two blocks of masses 3 kg and 5 kg approach each other with initial velocities 4 m/s and -6 m/s respectively. The two blocks col
Kipish [7]

Answer:

Explanation:

After the collision velocity of the particle is (4î - 3ĵ)m/s . ... A particle of mass 1 kg moving with a velocity of (4i^−3j^​)m/s collides with a fixed surface. ... Perfectly inelastic. D ... The common velocity of the blocks after collision is: ... A ball falls from a height of 5 m and strikes the roof of a lift. ... Stay upto date with our Newsletter! i know this is not right but just here for points see ya loser

6 0
2 years ago
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