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Ulleksa [173]
3 years ago
5

Energy is the ability to do.

Physics
2 answers:
pogonyaev3 years ago
7 0
Energy is the ability to do work
Aleks04 [339]3 years ago
6 0
Energy is the ability to do work
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A wave is moving between two mediums, as shown in the diagram below. The
wariber [46]

Answer:

Uhm i think its a

Explanation:

srry if i get it wrong ._. my bad

3 0
3 years ago
Can someone help me?
Cloud [144]

What do we know that might help here ?

-- Temperature of a gas is actually the average kinetic energy of its molecules.

-- When something moves faster, its kinetic energy increases.

Knowing just these little factoids, we realize that as a gas gets hotter, the average speed of its molecules increases.

That's exactly what Graph #1 shows.

How about the other graphs ?

-- Graph #3 says that as the temperature goes up, the molecules' speed DEcreases.  That can't be right.

-- Graph #4 says that as the temperature goes up, the molecules' speed doesn't change at all.  That can't be right.

-- Graph #2 says that after the gas reaches some temperature and you heat it hotter than that, the speed of the molecules starts going DOWN.  That can't be right.  

--

4 0
3 years ago
The chemical formula for water, H2O, means that each water molecule contains
Ainat [17]
The chemical formula for water, H2o means that each water molecule contains one oxygen atom and two hydrogen atoms. This is the formula for water which has a liquid form, a solid form as ice, and also a gaseous form as water vapor. 
5 0
3 years ago
Read 2 more answers
A parallel-plate capacitor has plates of area 0.40 m2 and plate separation of 0.20 mm. The capacitor is connected to a 9.0 V bat
mafiozo [28]

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC  

Explanation:

a)

  • By definition, the electric field is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

       E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)

b)

  • For a parallel-plate capacitor, applying the definition of capacitance as the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

       Q = \sigma* A (2)

        From (1), we know that V = E*d, but at the same time, applying Gauss'

        Law at a closed surface half within the plate, half outside it , it can be

        showed than E= σ/ε₀, so finally we get:

       C = \frac{Q}{V} =\frac{\sigma*A}{E*d}  = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)

c)    

  • From (3) we can solve for Q as follows:

       Q = C* V = 17.7 nF * 9.0 V = 159.3 nC  (4)

6 0
3 years ago
Please help me with homework
Stells [14]
<h3><u>Answer;</u></h3>

  = 64 N/m

<h3><u>Explanation</u>;</h3>

According to Hooke's Law for a helical spring or an elastic material, extensional force is directly proportional to the distance the material has extended.

F = ke; where F is the extension force, k is the spring constant, and e is the distance extended.

Thus;

k = F/e

  = 44N/0.69 m

  = 63.768 N/m

  <u>= 64 N/m</u>

8 0
3 years ago
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