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Ulleksa [173]
3 years ago
5

Energy is the ability to do.

Physics
2 answers:
pogonyaev3 years ago
7 0
Energy is the ability to do work
Aleks04 [339]3 years ago
6 0
Energy is the ability to do work
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What is the magnitude of the electric field at the dot in the figure? (figure 1)
blondinia [14]

The magnitude of the electric field at the dot is : 10⁴ v/m

<h3>What is electric field?</h3>

Electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

Given that there are three equipotential lines with equal spacing,we will apply the the relationship between P.D and electric field

Determine the magnitude of the electric field at the dot

change in voltage  = E .d

100 - 0 = E \times ( 1 \times 10^{-2}\  m ) ----- ( 1 )

From equation ( 1 )

The magnitude of electric field will be given as

E = \dfrac{100 }{ ( 1 \times  10^{-2})\ }

E = 10^4\ \ \frac {v}{   m}

Hence we can conclude that The magnitude of the electric field at the dot is :  10⁴ v/m

Learn more about electric field :

brainly.com/question/14372859

#SPJ4

5 0
2 years ago
Vad händer när man värmer gaser? ​
Anna [14]
Answer: Heating a gas increases the kinetic energy of the particles, which causes the gas to expand. But, I order to keep the pressure constant, the volume of the container must be increased when the gas is heated.
3 0
3 years ago
K20+H2O how many total oxygen atoms are there
kakasveta [241]
I think there would be 2 oxygen atoms,
If h2o is two hydrogen atoms and 1 oxygen atom then h2o has 2 potassium atoms and 1 oxygen atom, if you were to add them then together it would have 2 oxygen atoms, plz if I'm wrong correct me
8 0
3 years ago
Does fire use energy??
serious [3.7K]
No fire uses oxygen sparks and flammable wood or whatever you choose to burn
6 0
3 years ago
4. A group of students made a rocket and launched it vertically upwards with velocity
Aleks04 [339]

Answer:

Approximately 72.9\; \rm m, assuming that the rocket had no propulsion onboard, and that air resistance on the rocket is negligible.

Explanation:

Initial velocity of this rocket: u = 27\; \rm m\cdot s^{-1}.

When the rocket is at its maximum height, the velocity of the rocket would be equal to 0. That is: v = 0\; \rm m \cdot s^{-1}.  

The acceleration of the rocket (because of gravity) is constantly downwards, with a value of a = -g = -10\; \rm m \cdot s^{-2}.

Let x denote the distance that the rocket travelled from the launch site to the place where it attained maximum height. The following equation would relate x \! to u, v, and a:

\displaystyle x = \frac{v^2 - u^2}{2\, a}.

Apply this equation to find the value of x:

\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{\left(0\; \rm m\cdot s^{-1}\right)^{2} - \left(27\; \rm m \cdot s^{-1}\right)^{2}}{2 \times 10\; \rm m \cdot s^{-2}} = 36.45\; \rm m\end{aligned}.

In other words, the maximum height that this rocket attained would be 36.45\; \rm m.

Again, assume that the air resistance on this rocket is negligible. The rocket would return to the ground along the same path, and would cover a total distance of 2\times 36.45\; \rm m = 72.9\; \rm m.

7 0
3 years ago
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