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3 years ago

How many triangles can be formed from two given angle measures and the length of their included side?

Mathematics

1 answer:

Montano1993 [528]3 years ago

6 0

Answer:

b.One

Step-by-step explanation:

an infinite number of triangles can be formed if the judgement is on 2 angles but with 1 side length, the whole triangle needs to relate to the side of that side.

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Need help on both of them

Vlad1618 [11]

7) Write the decimal number as a fraction
(over 1)
2.18 = 2.18 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 2.18 × 10 × 10 × 10 = 2180
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 2180 / 1000

Simplifying our fraction

= 2180/1000

= 109/50

= 2 9/50

8) $7 ^{-5} = \frac{1}{7^{5}}$

6 0

3 years ago

Draw a diagram using positive an negative tiles for this equation:<br> -5-(-7)=2

Wewaii [24]

Sadly there is no way to graph properly on this website.

5 0

2 years ago

John is renting a car.The car cost 36 dollars each day plus $0.50 per mile over 100 miles.John rents the car for 5 days and driv

Deffense [45]

Answer:

36*5+80 =260

Step-by-step explanation:

hope this helps

6 0

2 years ago

The product of three integers x, x+2, and x-5 is 240. What are the integers?

Dafna11 [192]

Answer:

8, 10, 3

Step-by-step explanation:

For finding real solutions to cubic equations and those of higher degree, I find a graphing calculator to be useful. The problem can be cast in the form ...

f(x) = 0

where f(x) is the difference between the product of the integers and 240:

f(x) = x(x +2)(x -5) -240

Then all we need to do is ask the calculator to show the x-intercept. It is x=8.

So, the three integers are ...

x = 8
x+2 = 10
x -5 = 3

7 0

3 years ago

A baseball player comes up to bat 3 times during a league game. He either gets a hit or gets an out. How many different combinat

Stella [2.4K]

Answer:

8 different combinations are possible.

Step-by-step explanation:

Here, we have 2 different combinations for each time.

And the player comes out to bat 3 times.

So, total number of combinations are:

$2^{3}$ i.e. a total of 8 number of times.

Let a hit is termed as 'H' and an out is termed as 'O'.

Total combinations are:

{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}

Kindly have a look at the tree diagram attached in the answer area.

In starting, there are 2 combinations possible, i.e. 'O' and 'H'.

After 'O' , 2 possible i.e. 'O' and 'H'.

After 'H' , 2 possible i.e. 'O' and 'H'.

and so on....

8 0

3 years ago