The equation in this problem is: 2Pb(NO3)2(s) --> 2PbO(s)
+ 4NO2(g) + O2(g)
And the question is what the pressure in the cylinder is
after decomposition and cooling to a temperature of 300 K.
Solution:
Moles of Pb (NO3)2 = 3.31/331 = 0.0100
2 moles of Pb (NO3)2 will decay to mold 4 moles of NO2 and 1 mole of O2. So
0.0100 moles of Pb (NO3)2 will form 0.02 moles of NO2 and 0.00500 moles of
O2
Then use the formula: PV = nRT.
P = (0.02 + 0.005) * 0.082 * 300 / 1.62
= 0.380 atm
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Answer:
Please find the solution in the attachment file.
Explanation:
<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas
Average molar kinetic energy of the gas
E = 1/2 M * (V_rms)^2 = 8750 ms/1
So (V_rms)^2 = (2 * 8750) / M
Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3)
Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3))
(V_rms)^2 = 8750/0.035 = 250000
So V_rms = âš 250000 = 500</span>
Answer:
The correct answer is - 3.012×10^23 molecules
Explanation:
The number of molecules is present in any mole of an element or compound are the same. To find the molecules you need to multiply the number of the moles of the compound by Avogadro's number:
Moles are calculated from the molecular weight, for AlF3
= 26.98 + 3×19
= 26.98 + 57
= 83.98
Then moles in 42 grams:
= 42/83.98
= 0.5001190 moles
Now the number of molecules = moles*Avogadro's number
= 0.500110×6.022×10^23
= 3.011×10^23 molecules
Thank you :))) for the points have a great day
