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4 years ago

In which group of teh modern periodic table are there very reactive metals and very reactive non metals?

Chemistry

1 answer:

Rufina [12.5K]4 years ago

5 0

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

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A) A sample of ideal gas is in a sealed container. The pressure of the gas is 725 torr, and the temperature is 18 ∘C. If the tem

Fudgin [204]

Answer:

a. The new pressure is 606,25 Torr.

b. -243,9°C is needed to reach the pressure of 7250 Torr.

Explanation:

Gay Lussac's law for gases says that if the volume in a gas remains constant, the pressure will be directly proportional to the temperature change.

P1 . T1 = P2. T2

(Temperature must be in K)

725 Torr . 291 K = P2 . 348 K

(725 Torr . 291 K) /348 K = P2

606,25 Torr = P2

725 Torr . 291K = 7250 Torr . T2

(725 Torr . 291K) /7250 Torr = T2

29,1 K = T2

T° K - 273 = T°C

29,1 K -273 = -243,9°C

8 0

4 years ago

The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

Answer: The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

For $_{77}^{191}\textrm{Ir}$ isotope:

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

For $_{77}^{193}\textrm{Ir}$ isotope:

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

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3 years ago

WHO IS GOOD AT CHEMISTRY EQUATIONS? I NEED A QUESTION ANSWERED BY TONIGHT! ITS THE ONLY ONE IM STUCK ON:

sattari [20]

Answer:

374 atoms would be present in 22 units of aluminum sulfate.

Explanation:

Formula for Aluminium Sulfate : Al₂(SO₄)₃

Al = 2

S = 1

O = 4

(SO) = 3

∴ Number of atom in one unit is : 2 + (1+4)3 ==> 17

If there are 17 atoms in one unit, therefore;

Number of atoms in 22 units = 17 x 22

= 374 atoms

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3 years ago

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Answer:

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3 years ago

What is the main reason for processing coal ore?

seropon [69]

B) To remove inorganic material.

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3 years ago

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In which group of teh modern periodic table are there very reactive metals and very reactive non metals?​

In which group of teh modern periodic table are there very reactive metals and very reactive non metals?