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riadik2000 [5.3K]
3 years ago
8

During the experiment, scientists noted that several of the reaction beakers became hot to the touch. All of the following react

ions could cause this result except:____________.
Chemistry
1 answer:
Basile [38]3 years ago
4 0

During the experiment, scientists noted that several of the reaction beakers became hot to the touch. All of the following reactions could cause this result except endothermic and positive ∆H experiments.

<u>Explanation:</u>

If the beakers are becoming hot during experimentation, then that means the energy is being released from the reactants during this experiment. As the energy is being released that enthalpy change will also be negative as the enthalpy change is calculated as the difference of enthalpy of reactants from products.

So in these cases, heat is released making the beakers hot. So for the exceptional case, the experiment should be endothermic in nature and positive enthalpy change should be there in the experiment. Such that the heat will not be released leading to no heating of beakers.

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What is the volume of a box measuring 2cm by 3cm by 4cm?
grin007 [14]

I The answer is 42 cubic cm

3 0
2 years ago
Read 2 more answers
Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
Plz help :(
ziro4ka [17]
<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

Sr(NO_{3})_{2} is readily soluble in water.

Sr(NO_{3})_{2} dissolves in water to give Sr^{2+} ions and NO_{3}^{-} ions.

The reaction is

Sr(NO_{3})_{2}→Sr^{2+}+2NO_{3}^{-}

So,1 mole of Sr(NO_{3})_{2} gives 1 mole of Sr^{2+} and 2 moles of NO_{3}^{-}.

So,0.5 moles of Sr(NO_{3})_{2} gives 0.5 moles of Sr^{2+} and 1 mole of NO_{3}^{-}.

5 0
4 years ago
Can someone please check k these to see if I have any mistakes
iren [92.7K]
I do not see any mistakes so I think you’re good!
4 0
3 years ago
PLSSS HELP ANYONE ASAP!
algol [13]
B I hope it’s right I don’t really help a lot but yeah lol
7 0
3 years ago
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