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zzz [600]
3 years ago
6

What is the total number of molecules of hydrogen in 0.75 mole of hydrogen?

Chemistry
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

Explanation:

Avogadro's number, 6.022 * 1023 is the number of things in one mole. The question indicates that there is 1 mole of H2. Thus there are 6.022 * 1023 molecules of H2

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Atomic radius increases as you move down a group of elements.
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2 years ago
For this question, the "entropy term" refers to "-TΔS". Addition reactions are generally favorable at low temperatures because _
nata0808 [166]

Answer:

Lowering the temperature typically reduces the significance of the decrease in entropy. That makes the Gibbs Free energy of the reaction more negative. As a result, the reaction becomes more favorable overall.  

Explanation:

In an addition reaction there's a decrease in the number of particles. Consider the hydrogenation of ethene as an example.

\rm H_2C\text{=}CH_2\; (g) + H_2\; (g) \stackrel{\text{Ni}^\ast}{\to} H_3C\text{-}CH_3\; (g).

When \rm H_2 is added to \rm H_2C\text{=}CH_2 (ethene) under heat and with the presence of a catalyst, \rm H_3C\text{-}CH3 (ethane) would be produced.

Note that on the left-hand side of the equation, there are two gaseous molecules. However, on the right-hand side there's only one gaseous molecule. That's a significant decrease in entropy. In other words, \Delta S < 0.

The equation for the change in Gibbs Free Energy for a particular reaction is:

\Delta G = \Delta H + (\underbrace{- T \, \Delta S}_{\text{entropy}\atop \text{term}}).

For a particular reaction, the more negative \Delta G is, the more spontaneous ("favorable") the reaction would be.

Since typically \Delta S < 0 for addition reactions, the "entropy term" of it would be positive. That's not very helpful if the reaction needs to be favorable.

T (absolute temperature) is always nonnegative. However, lowering the temperature could help bring the value of

8 0
3 years ago
The force of 75 N must overcome in order to get the truck to start moving. What type of friction must be overcome?
Tamiku [17]

Answer:

Static Friction.

Explanation:

Friction is the force that resists the relative motion between the surfaces sliding against each other.

Static friction is friction between objects that are not in relative motion with each other.

The coefficient of static friction, typically denoted as  μs,

Static friction arises due to surface roughness( relative term)

The static friction force can be overcome by an applied  maximum force

F max =  μs x N

N= normal force

Any force smaller than F max attempting to slide one surface over the other is opposed by a frictional force of equal magnitude and opposite direction.

Any force larger than F max overcomes the force of static friction and causes sliding to occur.

This maximum force is sometimes called the limiting value also. Here that value is 75 N.

3 0
2 years ago
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