Answer:
Zero
Explanation:
The work done by a force on an object is given by:

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and the displacement of the object
In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so
and
. Therefore, the work done by gravity is also zero.
It is true ISHAHAAIWHAAOAWHSUS
Answer:
1.8nA
Explanation:
I = dq/dt
I = 9.0 × 10 ^-12 / 0.5 × 10^-3
I = 1.8 × 10× 10^-8
I = 1.8nA
Answer:
15116.4 V
Explanation:
B = Earth's magnetic field at the location = 
L = Length of the wire = 
v = Velocity of the shuttle = 
The emf generated is given by

The motional emf generated between the ends of the wire is 15116.4 V