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Oxana [17]
2 years ago
10

A ray of light in glass strikes a water-glass interface at an angle of incidence equal to one-half the critical angle for that i

nterface. The index of refraction for water is 1.33, and for the glass it is 1.43. What angle does the refracted ray in the water make with the normal
Physics
1 answer:
fomenos2 years ago
5 0

Answer:

Explanation:

There will not be any internal reflection . it will be only refraction

critical angle = θ

Sinθ = 1 / μg

μg = 1.43 / 1.33 =

Sinθ = 1.33 / 1.43

= .93

θ = 68.44

angle of incidence i = 68.44 / 2

= 34.22

Sin i / Sin r = μw = 1.33 / 1.43  

= .93

sin 34.22  / sinθ₁ = .93 , θ₁ is angle of refraction.

sinθ₁ = sin 34.22 / .93

= .5623 / .93

= .6047

θ₁ = 37 degree Ans

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The skittles because they are small so you can fit more in
3 0
3 years ago
A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω. The material constant, β, for this therm
Karo-lina-s [1.5K]

Answer:

the thermistor temperature = 325.68 \ ^0 \ C

Explanation:

Given that:

A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω.

i.e Temperature

T_1 = 100^0C\\T_1 = (100+273)K\\\\T_1 = 373\ K

Resistance of the thermistor R_1 = 20,000 ohms

Material constant \beta = 3650

Resistance of the thermistor R_2 = 500 ohms

Using the equation :

R_1 = R_2  \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})

\frac{R_1}{ R_2} =   \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})

Taking log of both sides

In \ \frac{R_1}{ R_2} = In \  \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})

In \ \frac{R_1}{ R_2} = {\beta} (\frac{1}{T_1}- \frac{1}{T_2})

\frac{ In \ \frac{R_1}{ R_2}}{ {\beta}} = (\frac{1}{T_1}- \frac{1}{T_2})

\frac{1}{T_2} =   \frac{1}{T_1}  -          \frac{ In \ \frac{R_1}{ R_2}}{ {\beta}}

{T_2} =  \frac{\beta T_1}{\beta - In (\frac{R_1}{R_2})T}

Replacing our values into the above equation :

{T_2} =  \frac{3650*373}{3650 - In (\frac{20000}{500})373}

{T_2} =  \frac{1361450}{3650 - 3.6888*373}

{T_2} =  \frac{1361450}{3650 - 1375.92}

{T_2} =  \frac{1361450}{2274.08}

{T_2} = 598.68 \ K

{T_2} = 325.68 \ ^0 \ C

Thus, the thermistor temperature = 325.68 \ ^0 \ C

4 0
3 years ago
A 120-V motor has mechanical power output of 2.50hp. It is 90.0% efficient in converting power that it takes in by electrical tr
EastWind [94]
  1. The current in this motor is equal to 17.27 Ampere.
  2. The energy delivered to this motor in 3.00 hours is equal to 22.38 Megajoules.
  3. At $0.110/kWh, the cost to run the motor for 3.00 hours is equal to $0.684.

<h3>How to determine the current (in A) delivered to the motor?</h3>

Assuming this electric motor is a single-phase motor and it operates by using DC current, its mechanical power output would be given by:

W = ηIV

Making current (I) the subject of formula, we have:

I = ηV/W

Substituting the given parameters into the formula, we have;

I = (2.50 × 0.746 × 1000)/(0.9 × 120)

I = 1,865/108

Current, I = 17.27 Ampere.

For the energy delivered to this motor, we have:

First of all, we would determine the power delivered to this motor as follows:

Power, P = IV

Power, P = 17.27 × 120

Power, P = 2,072.4 Watt.

Therefore, the energy delivered to this motor in 3.00 hours is given by:

Energy = power × time

Energy = 2,072.4 × 3.00 × 3,600 × 1/1000000

Energy = 22.38 Megajoules.

<h3>How to determine the cost?</h3>

At $0.110/kWh, the cost to run the motor for 3.00 hours is given by:

Cost = 0.110 × 22.38 × 0.278

Cost = $0.684.

Read more on energy here: brainly.com/question/15567897

#SPJ4

Complete Question:

A 120-V motor has mechanical power output of 2.50 hp. It is 90.0% efficient in converting power that it takes in by electrical transmission into mechanical power.

(a) Find the current in the motor.

(b) Find the energy delivered to the motor by electrical transmission in 3.00 h of operation.

(c) If the electric company charges $0.110/kWh, what does it cost to run the motor for 3.00 h?

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With each bounce off the floor, a tennis ball loses 11% of its mechanical energy due to friction. When the ball is released from
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Answer:

240 cm

Explanation:

Gradpoint

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10. What is the acceleration due to gravity at a location
kherson [118]
The answer is 3) 3.00 m/s2
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