A rocket ship at rest in space gives a short blast of its engine, firing 50 kg of exhaust gas out the back end with an average v
1 answer:
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For two un-related quantities, the Heisenberg uncertainty equations holds: the prduct of the two uncertainty quantities is greater than 
Example of unrelated quantities are position and momentum, energy and time.
Thus
Knowing the speed of the bacteria the uncertainty in its position is
Example of unrelated quantities are position and momentum, energy and time.
Thus
Knowing the speed of the bacteria the uncertainty in its position is
Answer:
The minimum frequency is 702.22 Hz
Explanation:
The two speakers are adjusted as attached in the figure. From the given data we know that
=3m
=4m
By Pythagoras theorem
Now
The intensity at O when both speakers are on is given by
Here
- I is the intensity at O when both speakers are on which is given as 6
- I1 is the intensity of one speaker on which is 6
- δ is the Path difference which is given as
- λ is wavelength which is given as
Here
v is the speed of sound which is 320 m/s.
f is the frequency of the sound which is to be calculated.
where k=0,1,2
for minimum frequency , k=1
So the minimum frequency is 702.22 Hz
