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Alinara [238K]
3 years ago
12

Which of the following describes work

Physics
2 answers:
Katena32 [7]3 years ago
8 0
Work is equal to force × distance, so the one that contains those describe work.
lifting 1kg of mass 1m is describing an upwards force and a distance if 1m, so that's the best answer
TEA [102]3 years ago
4 0
We know, Work done = force * displacement
So, in order to do a work, you need a force with displaced object.

Here, among all the options, objects are moving in 2 options, and only in last option, it does make sense, as it's product would be something finite value

In short, Your Answer would be Option D

Hope this helps!
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Balance the following chemical equations
IrinaVladis [17]

Answer:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

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To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} =...

Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2...

Explanation:

4 0
4 years ago
Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t
marin [14]

Answer:

Part a)

Q = 952 cal/day

Part b)

P = 46 Watt

Part c)

\Delta P = 54 W

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

m = 5000 kg

Q = 70,000 Cal

so we have energy required per kg

E = \frac{70,000}{5000}

E = 14 cal/kg

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

Q = 68 \times 14

Q = 952 cal/day

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

P = \frac{952 \times 4186}{24\times 3600}

P = 46 Watt

Part c)

resting power given in the book is

P' = 100 W

so this is less than the power given

\Delta P = 100 - 46

\Delta P = 54 W

6 0
3 years ago
A carpenter has a mix of both iron nails and plastic nails in a jar. For a job, he needs only the iron nails. What physical prop
ExtremeBDS [4]

Answer:

Magnetism

Explanation:

The carpenter can separate the iron nails from the plastic nails using a magnet. The iron nails have magnetic properties therefore they would be attracted to the magnet living only the plastic nails. This process is known as magnetic separation because it is based on the physical properties of the mixed components separating a mixture of components containing magnetic and non magnetic materials.

4 0
3 years ago
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Setler79 [48]
Circularity (especially formation of a circle of an orbit)
6 0
2 years ago
An air-filled parallel-plate capacitor is connected to a battery and allowed to charge up. Now a slab of dielectric material is
natita [175]

Answer:

The charge on the capacitor had increased

Explanation:

The expression for the capacitance of an air-filled parallel-plate capacitor is as follows as;

C=\frac{\epsilon _{0}A}{d}  

Here, C is the capacitance, \epsilon _{0} is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.

When a slab of dielectric material is placed between the plates of the capacitor then the expression for the capacitance is as follows;

C=\frac{K\epsilon _{0}A}{d}

Here, K is the dielectric constant.

In the given problem, a slab is inserted between the plates of the capacitor then the capacitance of the capacitor will increase in this case. Therefore, the option (a) is true.

The expression for the charge stored in the capacitor is as;

Q= CV

Here, Q is the charge and V is the potential.

The charge will also increase in this case as the charge stored in the capacitor is directly proportional to the capacitance. Therefore, the option (d) is not true.

The expression for the energy stored in the capacitor is as follows;

E=\frac{CV^{2}}{2}

The voltage is constant in the given problem but the capacitance increases then the energy stored in the capacitor will increase. Therefore, the option (b) is not true.

The voltage across the capacitor will remain same as the capacitor is still connected to the battery. Therefore, the option (c) is not true.

Therefore, only option (a) is true.

3 0
3 years ago
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