a bike is moving with a velocity of 90km/hr.after applying break it stops in 5 sec. calculate the force applied by brakes .mass
1 answer:
You might be interested in
The angular speed of the device is 1.03 rad/s.
<h3>What is the conservation of angular momentum?</h3>A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.
Using the conservation of angular momentum
Here, = the system's angular momentum before the collision
= 0 + mv
= (0.005)(450)(0.752)
= 1.692 kgm²/s
The moment of inertia of the system is given by
I = 2(M₁R₁² + M₂R₂²)+ mR₁²
= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²
= 1.6292 kgm²
Here, = Iω
So,
1.692 = 1.6292(ω)
ω = 1.03 rad/s
To know more about the conservation of angular momentum, visit:
#SPJ1
Answer:
part (a) v = 1.7 m/s towards right direction
part (b) Not an elastic collision
part (c) F = -228.6 N towards left.
Explanation:
Given,
- Mass of the first puck =
- Mass of the second puck =
- initial velocity of the first puck =
- Initial velocity of the second puck =
Part (a)
Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.
From the conservation of linear momentum,
Direction of the velocity is towards right due to positive velocity.
part (b)
Given,
Final velocity of the second puck =
Let be the final velocity of first puck after the collision.
From the conservation of linear momentum,
For elastic collision, the coefficient of restitution should be 1.
From the equation of the restitution,
Therefore the collision is not elastic collision.
part (c)
Given,
Time of impact = t =
we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,
Negative sign indicates that the force is towards in the left side of the movement of the first puck.