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borishaifa [10]
3 years ago
7

a bike is moving with a velocity of 90km/hr.after applying break it stops in 5 sec. calculate the force applied by brakes .mass

of motercycle and rides is 200 kg
Physics
1 answer:
pentagon [3]3 years ago
7 0

Explanation:

initial velocity(u) = 90 km/s = 25 m/s

time (t) = 5 sec

mass (m) = 200 kg 

final velocity (v) = 0 m/s

v = u + at 

0 = 25 + a * 5

-25 = 5 a

-5 = a

Therefore acceleration = -5m/s²

Force = mass * acceleration 

F = 200*-5

F = -1000 N

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The correct option is C) The angle between the vectors is 120°.

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We can solve the problem and find the correct option using the Law of Cosine.

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R^{2}=A^{2}+B^{2}+2ABCos(\alpha)\\ \\A^{2}=A^{2}+A^{2}+2*A*A*Cos(\alpha)\\\\0=A^{2}+2*A^{2}*Cos(\alpha)\\\\Cos(\alpha)=-\frac{A^{2}}{2*A^{2}}=-\frac{1}{2}\\\\\alpha =Cos(-\frac{1}{2})^{-1}=120\°

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3 years ago
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v=2\times3.14\times 1.50\times0.75 = 9.42\times0.75 = 7.065=7.07

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