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ICE Princess25 [194]
3 years ago
11

The internal energy of a system is always increased by __________. a adding heat to the system and having the system do work on

the surroundings b having the system do work on the surroundings c withdrawing heat from the system d a volume compression e adding heat to the system
Physics
1 answer:
Nitella [24]3 years ago
8 0
There are two correct options:
<span>d) a volume compression
e) adding heat to the system

In fact, we can have a look at the first law of thermodynamics:
</span>\Delta U = Q-W
<span>where
</span>\Delta U is the variation of internal energy
<span>Q is the heat absorbed by the system
W is the work done by the system on the surrounding

It is important to keep in mind the right sign convention for Q and W: Q is positive when the heat is absorbed by the system, while it is negative when it is released by the system; W is positive when it is done by the system on the surrounding, and negative when it is done by the surrounding on the system.

Using this convention, we can see that:
d) when there is a volume compression, the work is done by the surrounding on the system, so the work is negative, and the variation of internal energy is positive due to the negative sign -W in the first law of thermodynamics
e) when heat is added to the system, Q is positive, so the variation of internal energy is positive as well</span>
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Answer:

v=2.02\frac{m}{s}

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v=x\sqrt\frac{k}{m}\\v=2.63*10^{-2}m\sqrt{\frac{5.9*10^6\frac{N}{m}}{10^3kg}}\\v=2.02\frac{m}{s}

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m = mass of the car moving in horizontal circle = 1750 kg

v = Constant speed of the car moving in the horizontal circle = 15 m/s

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F = m v²/r

inserting the above values in the formula

F = (1750) (15)²/(45)

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A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of
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Answer:

Explanation:

Given that,

Mass attached to spring

M = 0.52kg

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Amplitude A = 11.6 cm

a. Maximum speed?

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w = √k/m

w = √8/0.52

w = √15.385

w = 3.922rad/s

Then, the relation ship between angular velocity and linear velocity is given as

v = - w•A

v = - 3.922 × 11.6

v = - 45.5 cm/s

Then, the maximum velocity is

vmax = |v|= 45.5cm/s

b. Acceleration a?

Acceleration can be determine using the formula

a = -w²• A

a = -3.922² × 11.6

a = -178.46 cm/s²

Magnitude of the acceleration is 178.46cm/s²

c. Speed when the object is at 9.6cm from equilibrium position?

Generally,

The position of the object at equilibrium is

x(t) = A•Cos(wt)

x(t) = 11.6 Cos (3.922t)

Then, when x(t) = 9.6cm

9.6 = 11.6 Cos(3.92t)

Cos(3.922t) = 9.6/11.6

Cos(3.922t) = 0.8276

3.922t = ArcCos(0.8276)

Note: the angle is in radiant

3.922t = 0.596

t = 0.596/3.922

t = 0.152 second

Then, v(t) at that time is

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Now, when t =0.152

v(t) = -45.5 Sin(3.922×0.152)

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v(t) = -25.5 cm/s

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Magnitude of the acceleration is 147.68 cm/s²

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