Question

What are the solutions to the inequality (x-3)(x+5)greater than and =0​

Answer 1

Answer: $(-\infty,-5]\ U\ [3,\infty)$

Step-by-step explanation:

Given the inequality $(x-3)(x+5)\geq 0$, to find the solutions, we need to follow this procedure:

- First case:

$x-3\geq 0$ and  $x+5\geq 0$

Solve for the variable "x":

$x\geq 0+3\\x\geq 3$

 $x\geq 0-5\\x\geq -5$

Then:

$x\geq 3$

- Second case:

$x+5\leq 0$ and $x-3\leq 0$

Solve for the variable "x":

$x\leq 0-5\\x\leq -5$

$x\leq 0+3\\x\leq 3$

Then:

$x\leq-5$

Finally, the solution is:

$(-\infty,-5]\ U\ [3,\infty)$

Answer 2

Answer:

3 and -5

Step-by-step explanation:

(x-3)(x+5)greater than and =0​

separate

(1).

x - 3 > 0

add 3 to both sides

x > 3

(2).

x + 5 > 0

subtract 5 from both sides

x > -5

So, The solutions are 3 and -5