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3 years ago

Volume of box is 30cm cube breadth is 5cm height is 2m find length

Physics

1 answer:

lutik1710 [3]3 years ago

7 0

Answer:

3 cm

Explanation:

I think the question have some error because if height = 2 m = 200cm.

Volume of box = l * b * h

V = 30 cm³

b = 5 cm

h = 2 cm

l = ?

V = l * b * h

30 cm³ = l * 5 * 2

l = 30 / 10

l = 3 cm

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What minimum volume must the slab have for a 75.0 kgkg woman to be able to stand on it without getting her feet wet

Alisiya [41]

V = 0.9375 m3 is minimum volume .

<h3>What is density ?</h3>

We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the amount of matter contained therein (its mass).
Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small.

Given,

1000 kg/m3 = density of water

920 kg/m3 = density of ice

BF = Woman Weight + Slab Weight

Pvg = 75 + Pvg

V = 75 kg / (1000 - 920)

V = 75 / 80

V = 0.9375 m3

Therefore, V = 0.9375 m3 is minimum volume .

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2 years ago

Calculate the first and second order angles for light of wavelength 400. nm and 700. nm of the grating contains 1.00 x 104 lines

Verdich [7]

Answer:

$23.58^{\circ}$ and $53.13^{\circ}$

$44.43^{\circ}$ , second order does not exist

Explanation:

n = Number of lines grating = $1\times10^4\ \text{Lines/cm}$

$\lambda$ = Wavelength

m = Order

Distance between slits is given by

$d=\dfrac{1}{n}\\\Rightarrow d=\dfrac{1}{1\times 10^4}\\\Rightarrow d=10^{-6}\ \text{m}$

$\lambda=400\ \text{nm}$

m = 1

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\\\Rightarrow \theta=\sin^{-1}\dfrac{1\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=23.58^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=53.13^{\circ}$

The first and second order angles for light of wavelength 400 nm are $23.58^{\circ}$ and $53.13^{\circ}$ .

$\lambda=700\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 700\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=44.43^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 700\times 10^{-9}}{10^{-6}}$

Here $\dfrac{2\times 700\times 10^{-9}}{10^{-6}}=1.4>1$ so there is no second order angle for this case.

The first order angle for light of wavelength 700 nm are $44.43^{\circ}$ .

Second order angle does not exist.

5 0

3 years ago

Determine the mechanical energy of this object. A 2 kg pendelum has a speed of 1 m/s at a height of 1/2 meter

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Mechanical Energy: 10.81 J given that $g = 9.81 \; \text{m}\cdot\text{s}^{-2}$ .

<h3>Explanation</h3>

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3 years ago

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3 years ago

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ch4aika [34]

Explanation:

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