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sashaice [31]
3 years ago
6

How many grams of iron metal do you expect to be produced when 275 grams of an 65.5 percent by mass iron (II) nitrate solution r

eact with excess aluminum metal? Show all of the work needed to solve this problem.
2Al (s) + 3Fe(NO3)2 (aq)yields 3Fe (s) + 2Al(NO3)3 (aq) (4 points)
Chemistry
2 answers:
umka21 [38]3 years ago
8 0
75.5 I hope this helps
Jlenok [28]3 years ago
4 0

Answer:

75.5

Explanation:

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In a certain time, light travels 4.96 km in a vacuum. during the same time, light travels only 3.36 km in a liquid. what is the
Natali5045456 [20]

the refractive index of the liquid is 1.476

The refractive index, which has no dimensions, measures how quickly light passes through a substance.

It can also be described as the difference between the speed of light in a vacuum and a medium.

Refractive index is equal to the product of the light's liquid and vacuum speeds.

Therefore.

speed of light in vacuum = 4.96 km/t

speed of light in liquid = 3.36 km/t

Refractive index = 4.96/3.36

Refractive index =1.476

Therefore, the refractive index of the liquid is 1.476

To learn more about refractive index

brainly.com/question/23750645

#SPJ4

6 0
1 year ago
Chemistry - please help!!​
Ira Lisetskai [31]

Answer: mnikbm gv mvb mmbiofikfbjm

Explanation:

4 0
1 year ago
I did this on accident lol
k0ka [10]
Hey what is ur question
5 0
3 years ago
Read 2 more answers
Joan’s initial nickel (II) chloride sample was green and weighed 4.3872 g. After the dehydration reaction and removal of excess
ANEK [815]

Answer:

a) yes, it was an hydrate

b) the number of waters of hydration, x = 6

Explanation:

a) yes it was an hydrate because the mass decreased after the process of dehydration which means removal of water thus some water molecules were present in the sample.

b) NiCl2. xH2O

mass if dehydrated NiCl2 = 2.3921 grams

mass of water in the hydrated sample = mass of hydrated - mass of dehydrated = 4.3872 - 2.3921 = 1.9951 g which represent the mass of water that was present in the hydrated sample.

NiCl2.xH2O

mole of dehydrated NiCl2 = m/Mm = 2.3921/129.5994 = 0.01846 mole

mole of water = m/Mm = 1.9951/18.02 = 0.11072 mole

Divide both by the smallest number of mole (which is for NiCl2) to find the coefficient of each

for NiCl2 = 0.01846/0.01846 = 1

for H2O = 0.11072/0.01846 = 5.9976 = 6

thus the hydrated sample was NiCl2. 6H2O

4 0
3 years ago
What is the molarity of the solution resulting from the dissolution of 239 g glucose (C6H12O6) in 250
kifflom [539]

Answer:

Molarity =5.32 M

Explanation:

Given data:

Mass of glucose = 239 g

Volume = 250 mL (250 /1000 = 0.25 L)

Molarity = ?

Solution;

Formula:

Molarity = number of moles / volume in litter

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 239 g / 180.2 g/mol

Number of moles = 1.33 mol

Molarity:

Molarity = number of moles / volume in litter

Molarity = 1.33 mol / 0.25 L

Molarity =5.32 M

6 0
3 years ago
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