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sashaice [31]
3 years ago
6

How many grams of iron metal do you expect to be produced when 275 grams of an 65.5 percent by mass iron (II) nitrate solution r

eact with excess aluminum metal? Show all of the work needed to solve this problem.
2Al (s) + 3Fe(NO3)2 (aq)yields 3Fe (s) + 2Al(NO3)3 (aq) (4 points)
Chemistry
2 answers:
umka21 [38]3 years ago
8 0
75.5 I hope this helps
Jlenok [28]3 years ago
4 0

Answer:

75.5

Explanation:

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We have the relation

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The new concentration is 0.05\ \text{M HCl}.

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