Answer:
Molecular Formula => (CH₂)₇ => C₇H₁₄
Explanation:
Empirical ratio is calculated from the sequence...
%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio => Empirical Ratio
C: 85.7% => 85.7g => (85.7/12)mol = 7.14 mole
H: 14.3% => 14.3g => (14.3/1)mol = 14.3 mole
C:H mole ratio => 7.14:14.3
Reduced mole ratio (divide by the smaller mole value) => (7.14/7.14):(14.3/7.14) => Empirical Ratio => 1:2 => Empirical Formula => CH₂
Molecular Wt = Whole No. Multiple of Empirical Formula Wt.
M.Wt = N(Emp Wt) => 98g = N(14g) => N = 7
∴Molecular Formula => (CH₂)₇ => C₇H₁₄
The base gram of the compound is 16.042
To find the new amount of grams, you need to multiply the amount of moles by the the base grams
16.042*.25=4.01
So one fourth of the compound is 4.01 grams of Carbon tetrahydride.
Answer:
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First, write out a complete balanced reaction for the combustion of ethane, ethane + O2 -> CO2 + H20. Then, divide the grams of ethane by its Molar Mass and multiply by 32, the molar mass of O2.
