All categories

3 years ago

7. If 100.0 grams of Hydrogen burns, how many moles of Water will form?

Chemistry

1 answer:

yan [13]3 years ago

5 0

50moles of H₂O

Explanation:

Given parameters:

Mass of hydrogen burning = 100g

Unknown:

Number of moles of water formed = ?

Solution:

To solve this problem, we have to apply the mole's concept. We should first obtain the balanced equation for the reaction. Then express the mass as moles and compared to that of water.

Solve from the known to the unknown;

Equation:

2H₂ + O₂ → 2H₂O

Number of moles of Hydrogen gas = $\frac{mass}{molar mass}$

Molar mass of H₂ = 2(1) = 2g/mol

Number of moles = $\frac{100}{2}$ = 50moles

From the equation of the reaction;

2 mole of H₂ produced 2 mole of H₂O;

Then 50 mole of H₂ will produce 50moles of H₂O

50 mole of water will be formed

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

You might be interested in

A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513

igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is: N₂O₄(g) ⇆ 2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

2NO₂ (g) ⇆ N₂O₄(g)

Initially 2.20 mol -

React x x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq (2.20-x) / 3.50L (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) / [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0 → Quadratic formula

a = 0.2933 ; b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50 = 0.0971 M

8 0

2 years ago

ANSWER ASAP AND I WILL GIVE BRAINLYEST!!!!

den301095 [7]

Answer:

Explanation:

8 0

3 years ago

42. Proton and electuron.

Sauron [17]

Answer:

Protons:

- positive

- aka cation

- in the nucleus along with the neutrons

Electrons:

- negative

- aka anion

- situated in the orbital shells/configuration levels (there are many names)

7 0

2 years ago

Which of the following is true of science? (2 points)

Tju [1.3M]

Answer:

It is based on testable and replicable evidence.

7 0

2 years ago

HURRY HELP 10 POINTS ILL GOVE BRAINLIEST I HAVE TO PASS PICTURE PROVIDED

kramer

Answer:

C₃H₄O₄

Explanation:

In order to get the empirical formula of a compound, we have to follow a series of steps.

Step 1: Divide the percent by mass of each element by its atomic mass.

C: 34.6/12.01 = 2.88

H: 3.9/1.01 = 3.86

O: 61.5/16.00 = 3.84

Step 2: Divide all the numbers by the smallest one, i.e., 2.88

C: 2.88/2.88 = 1

H: 3.86/2.88 ≈ 1.34

O: 3.84/2.88 ≈ 1.33

Step 3: Multiply all the numbers by a number that makes all of them integer

C: 1 × 3 = 3

H: 1.34 × 3 = 4

O: 1.33 × 3 = 4

The empirical formula is C₃H₄O₄.

5 0

3 years ago