Answer:
0.0126 moles are released
Explanation:
Using Henry's law, where the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid:
S = k×P
<em>Where S is solubility (5.6x10⁻⁴molL⁻¹), k is Henry's constant and P is partial pressure (0.80atm)</em>
Replacing:
<em>5.6x10⁻⁴molL⁻¹ / 0.80atm = 7x10⁻⁴molL⁻¹atm⁻¹</em>
Thus, with Henry's constant, solubility of N₂ when partial pressure is 3.8atm is:
S = 7x10⁻⁴molL⁻¹atm⁻¹ × 3.8atm
S = 2.66x10⁻³molL⁻¹
Thus, when the deepd-sea diver has a pressure of 3.8amt, moles dissolved are:
6.0L × 2.66x10⁻³molL⁻¹ = <em>0.01596 moles of N₂</em>
At the surface, pressure is 0.80atm and solubility is 5.6x10⁻⁴molL⁻¹, moles dissolved are:
6.0L × 5.6x10⁻⁴molL⁻¹ = <em>3.36x10⁻³mol</em>
Thus, released moles are:
0.01596mol - 3.36x10⁻³mol = <em>0.0126 moles are released</em>
