Lipids are organic molecules which can be used for long-term energy. These includes fats, waxes, sterols, glycerides, phospholipids, etc. Lipids contain more energy per unit mass which makes it much lighter. However, their insolubility to water makes them harder to transport.
Answer:
0.683 mol
46.3 g
Explanation:
There is some info missing. I think this is the original question.
<em>Boron trifluoride gas is collected at 21.0 °C in an evacuated flask with a measured volume of 50.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.330 atm. Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to 3 significant digits.</em>
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Step 1: Convert the temperature to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 21.0°C + 273.15
K = 294.2 K
Step 2: Calculate the moles of boron trifluoride gas
We will use the ideal gas equation.
Step 3: Calculate the mass of boron trifluoride gas
The molar mass of BF₃ is 67.81 g/mol.
I believe the correct answer from the choices listed above is option C. You would classify this solution as basic since it has the pH of more than 7 which signifies a basic solution. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
Two compounds.
Explanation:
If you have two peaks in your gas chromatograph, this means that you have two compounds.
The gas chromatograph is an instrument that helps identify how many compounds a substance has by observing its behavior against a solid medium through adsorption and the velocity of each compound in it.
The volume of CO2 at STP =124.298 L
<h3>Further explanation</h3>
Given
Reaction
4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O
701,52 g of KMnO4
Required
volume of CO2 at STP
Solution
mol KMnO4 (MW=158,034 g/mol) :
mol = mass : MW
mol = 701.52 : 158.034
mol = 4.439
mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549
At STP 1 mol = 22.4 L, so for 5.549 moles :
=5.549 x 22.4
=124.298 L
