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statuscvo [17]
3 years ago
12

How does an object's weight vary on other celestial bodies?

Physics
1 answer:
7nadin3 [17]3 years ago
8 0
Object weight varues on cellestial bodies due to the acceleration due to gravity acting on the body. the acc due to gravuty depend on the mass and radius of the cellestial body. Thus the weight varies on cellestian bodies
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A cat pushes a mouse horizontally on a frictionless floor with a net force of 1.0 N 1.0N1, point, 0, start text, N, end text for
vesna_86 [32]

Answer: 3

Explanation:

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3 years ago
With a 900 V source, voltage is divided across 3 series resistors of 300 V, 280 V, and:
telo118 [61]

Answer:

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two bumper cars collide into each other and each caor jolts backwards what law is this isnt it newtons second law?
Yanka [14]
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5 0
3 years ago
Calculate the root mean square velocity of nitrogen molecules at 25°c.
umka2103 [35]

Answer:

515.22 m/s

Explanation:

Formula for root mean square velocity is SQRT (3RT/M)

Where,

R = Rydberg's constant = 8.314 Kg. m²/ s². K. mol

T = Temperature in Kelvin

M = Molar mass in Kg/mol

First calculate molar mass,

As nitrogen is diatomic molecule,

Its molar mass is

M = 2(14) = 28 g/mol

Convert unit into Kg/mol

28 g/mol x 1 Kg/1000g = 2.8x10¯² Kg/mol

Convert temperature into kelvin

T = 25 + 273 = 298K

Put all values in formula

Vrms = SQRT (3RT/M)

Vrms = SQRT (3x8.314x298/2.8x10¯²)

Vrms = SQRT (265454. 14)

Vrms = 515.22 m/s

5 0
3 years ago
s) A body of mass 2 kilograms moves on a circle of radius 3 meters, making one revolution every 5 seconds. Find the magnitude of
jeyben [28]

Answer:

Centripetal force acting on the body = 9.47 N

Explanation:

Mass of body, m = 2 kg

Radius, r = 3 m

It makes one revolution in 5 seconds.

        Period, T = 5 s

        \texttt{Angular velocity, }\omega =\frac{2\pi }{T}=\frac{2\pi }{5}=1.256rad/s

Centripetal force, F = mrω²

                        F = 2 x 3 x 1.256² = 9.47 N

Centripetal force acting on the body = 9.47 N

8 0
3 years ago
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