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Ganezh [65]
3 years ago
14

How can scientist best confirm and validate the result of an experiment so they can publish their findings?

Physics
2 answers:
vladimir2022 [97]3 years ago
7 0

Answer:. By creating a replicable experiment

Explanation:

ValentinkaMS [17]3 years ago
5 0

Question

How can scientist best confirm and validate the result of an experiment so they can publish their findings?

Answer:

Hi, there!

D. By creating a replicable experiment Is The correct Answer!

Hope this Helps!!

-xXxAnimexXx- ♚♛♕♔ッ✨♚

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25 points! Please someone help me, this seems like a pretty easy question but I can’t seem to get it right, please list the give
elixir [45]

Answer:

1 my brother say that

Explanation:

i know my brother said it

4 0
2 years ago
Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh
larisa [96]

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

\mu = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

4 0
3 years ago
You are retrieving your boat from the water. as a courtesy to others, when should you pull your boat into a launch lane?
OLga [1]
The best way to pull the boat in the launch lane is when the towing vehicle has reached the boat ramp as well as the trailer. It is best to retrieve the boat in this manner for it is more appropriate, convenient and it is a way of showing courtesy towards others because it is a proper manner.
7 0
3 years ago
Read 2 more answers
A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed
fgiga [73]

Answer:

Explanation:

Time taken to accelerate to 28 m /s

= 28 / 2 = 14 s

a ) Total length of time in motion

= 14 + 41 + 5

= 60 s .

b )

Distance covered while accelerating

s = ut + 1/2 at²

= 0 + .5 x 2 x 14²

= 196 m .

Distance covered while moving in uniform motion

= 28 x 41

= 1148 m

distance covered while decelerating

v = u - at

0 = 28 - a x 5

a = 5.6 m / s²

v² = u² - 2 a s

0 = 28² - 2 x 5.6 x s

s = 28² / 2 x 5.6

= 70 m .

Total distance covered

= 196 + 1148 + 70

= 1414 m

total time taken = 60 s

average velocity

= 1414 / 60

= 23.56 m /s .

8 0
3 years ago
In a nuclear fusion reaction, the mass of the products is _____ the mass of the reactants.
JulijaS [17]

Answer:

more than

Explanation:

In a nuclear fusion reaction, the mass of the products is more than the mass of the reactants.

7 0
3 years ago
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