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pychu [463]
2 years ago
7

All of the following steps are included in a self-modification program except __________. A. specifying target behavior B. desig

ning a program C. focusing on one goal at a time D. gathering data about target behavior
(Psychology)
Physics
2 answers:
Y_Kistochka [10]2 years ago
8 0

Answer:

C)focusing on one goal at a time

Explanation:

Self-modification programs could be regarded as a program that help individual in managing unwanted as well as dysfunctional behavioral responses whenever they are going through a problem and try to deal with it. For instance the dysfunctional behavioral response for someone with a panic attack is avoidance. Some of the the steps that are involved in in a self-modification program are;

✓ specifying target behavior ✓designing a program

✓ gathering data about target behavior

nevsk [136]2 years ago
5 0

Answer:

c

Explanation:

on edge 2020

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An applied pulling force of 100 N is used to accelerate an object to the right along a rough surface that offers 40 N of frictio
blondinia [14]

Answer:

9.8 m/s^2

Explanation:

First of all, we analyze the vertical direction.

Along this direction, the object is in equilibrium, so its acceleration is zero, and therefore  the net force on it is zero. There are only two forces acting on the object vertically: the weight, W (downward), and the normal force, N (upward), and since the net force must be zero, we can write

W=N

And since N = 60 N, the weight of the object is

W = 60 N

From this, we can also find the mass of the object, using the equation:

W=mg \rightarrow m = \frac{W}{g}=\frac{60}{9.8}=6.1 kg

where g=9.8 m/s^2 is the acceleration of gravity.

Now we analyze the forces along the horizontal direction. We have:

A pulling force of F=100 N forward

A frictional resistance of F_f = 40 N backward

So the equation of motion in this direction is

F-F_f = ma

And solving for a, we find the acceleration of the object:

a=\frac{F-F_f}{m}=\frac{100-40}{6.1}=9.8 m/s^2

in the horizontal direction, forward.

4 0
2 years ago
The actual mass of a cl 37 atom is 36.966 amu. calculate the mass defect ( amu/atom) for a cl 37 atom​
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Answer:

The mass defect Δm = 0.33626 amu

Explanation:

Given,

The actual mass of a Cl 37 atom, m = 36.966 amu

The atomic number of Cl is 17. Hence, chlorine has <em>17 protons</em>,

Therefore, the Cl 37 has <em>20 neutrons</em>

The mass of 1 proton = 1.00728 amu

The mass of 1 neutron = 1.00867 amu

The mass of 17 protons = 17 x 1.00728 = 17.12886 amu

The mass of 20 protons = 20 x 1.00867 = 20.1734 amu

The total mass of proton and neutron, M = 37.30226 amu

The mass defect is defined as the difference in the sum of the mass of protons and neutrons of the nucleus of an atom to the actual mass of the nucleus.

Therefore,

                        Δm = M - m

                               =  37.30226 - 36.966

                               = 0.33626 amu

Hence, the mass defect of the Cl 37 atom is, Δm = 0.33626 amu

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3 years ago
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Explanation:

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F_2=214.8\ N

So, if the speed is 18 m/s, then the horizontal force acting on the car is 214.8 N. Hence, this is the required solution.

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