Answer:
The latent heat of vaporization of water is 2.4 kJ/g
Explanation:
The given readings are;
The first (mass) balance reading (of the water) in grams, m₁ = 581 g
The second (mass) balance reading (of the water) in grams, m₂ = 526 g
The first joulemeter reading in kilojoules (kJ), Q₁ = 195 kJ
The second joulemeter reading in kilojoules (kJ), Q₂ = 327 kJ
The latent heat of vaporization = The heat required to evaporate a given mass water at constant temperature
Based on the measurements, we have;
The latent heat of vaporization = ΔQ/Δm
∴ The latent heat of vaporization of water = (327 kJ - 195 kJ)/(581 g - 526 g) = 2.4 kJ/g
The latent heat of vaporization of water = 2.4 kJ/g
Answer:
Hello todays answer should be False i am sorry if i am incorrect-Lucy
Explanation:
The transfer of energy is potential energy to kinetic energy. The swing has potential energy when she pulls it back and once she lets go, allowing the swing to move, it then has kinetic energy.
Answer:
Answer is D
Explanation:
By changing the direction of the current moving through the wire will change polarity of the magnet but it will not affect the strength of the magnet.
