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4 years ago

NO Assign oxidation numbers to each element in this compound.

Chemistry

1 answer:

marta [7]4 years ago

7 0

Answer:

N=+2

O=-2

Explanation:

The compound NO is electrically neutral.

Lets assign the oxidation number of nitrogen to be N. The oxidation number of oxygen (-2) is then used as a reference.

For the compound to have a zero charge, sum of the oxidation numbers equals zero.

N+ (-2)=0

N=+2

O=-2

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Use the information from the diagram to calculate the enthalpy of combustion for methane. (HELP ASAPPP!!)

Blizzard [7]

Answer:

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3 years ago

A balloon is filled with 30L of helium gas at 1atm.What is the volume when balloon rises to an attitude where the pressure is on

Harrizon [31]

Answer:

$V_2=120L$

Explanation:

Hello!

In this case, since Helium is undergoing a volume-pressure change, according the Boyle's law, we infer the following equation is used:

$P_1V_1=P_2V_2$

Thus, since we are not given the volume at 0.25 atm, we can solve for V2 to do so:

$V_2=\frac{P_1V_1}{P_2}$

Thus, we plug in to obtain:

$V_2=\frac{1atm*30L}{0.25atm}=120L$

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7 0

3 years ago

4. How many atoms are contained in 3.55 moles of sodium chloride?

DochEvi [55]

Hey there!

There are 6.022 x 10²³ particles in 1 mole.

We have 3.55 moles.

6.022 x 10²³ x 3.55

2.14 x 10²⁴

This is how many particles we have.

NaCl has 2 atoms for every unit.

So we multiply this by 2.

2 x 2.14 x 10²⁴ = 4.28 x 10²⁴

There are 4.28 x 10²⁴ atoms in 3.55 moles of sodium chloride.

Hope this helps!

5 0

4 years ago

Read 2 more answers

Can a compound have more than one carbon-carbon double bond in it?

kiruha [24]

Answer:

yes, a compound can have more than one carbon-carbon double bond

4 0

3 years ago

11mg of cyanide per kilogram of body weight is lethal for 50% of domestic chickens. How many grams per kilogram of body weight i

Nookie1986 [14]

Answer:

$0.033g$

Explanation:

Hello,

In this case, since 11 mg per kilogram of body weight has the given lethality, the mg that turn out lethal for a chicken weighting 3 kg is computed by using a rule of three:

$11mg\longrightarrow 1kg\\\\x\ \ \ \ \ \ \longrightarrow 3kg$

Thus, we obtain:

$x=\frac{3kg*11mg}{1kg}\\ \\x=33mg$

That in grams is:

$=33mg*\frac{1g}{1000mg} \\\\=0.033g$

Regards.

7 0

3 years ago