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Amiraneli [1.4K]

3 years ago

10

How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?

1 answer:

maw [93]3 years ago

4 0

Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation

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3 0

3 years ago

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

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2 years ago

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Sladkaya [172]

The is no picture???????

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