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3 years ago

How many g of MgCO3(s) are needed to make 1.2 L of 1.5 M MgCl2(aq) solution?

1 answer:

4 0

Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol

Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation

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Explanation:

The given data is as follows.

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Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

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= 6.118 Torr + 32.1575 Torr

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Composition of $CCl_{4}$ is 0.8405 .

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