Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
-195 degrees
Step-by-step explanation:
we can subtract 360 from 165 to find the negative coterminal angle.
165-360=-195
<span>the answer is C. x ≥ 8.00 and x < 9.50
proof
</span>x ≥ 8.00 is equivalent to 8.00 ≤ x, and we have also <span>x < 9.50
so </span>x ≥ 8.00 and x < 9.50 or <span>8.00 ≤ x < 9.50</span>
Add 3 1/2 and 2 1/3,
Firstly, find the common denominator. It is is 6
3 3/6 + 2 2/6
this gets you 5 5/6.
Take this away from 8:
8 - 5 5/6 = 2 1/6
So 2 1/6 of the board is left over.
