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katen-ka-za [31]
3 years ago
15

Dave throws a 10 kg bowling ball straight up in the air. At the very tippy-top of its path, what is it's momentum?

Physics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer:Zero

Explanation:

Given

mass of ball m=10\ kg

If the ball is thrown upward then at maximum point velocity of ball is zero because ball is no longer able to move upward

Momentum(P) of a particle is given by

P=mass\times velocity

P=10\times 0

P=0

Therefore at the highest point momentum is zero .

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A cheetah ran 300 feet in 2.92 seconds. What was the cheetah’s average speed in miles per hour?
olganol [36]
We will first convert feet to miles:
1 foot = 0.00018939 miles
300 foot = 0.056817 miles
Than seconds to hours:
2.92 seconds = 0.04867 minutes = 0.0008111 hours
Average speed :
v = d / t
v = 0.056817 miles / 0.008111 h
v = 70.05 miles per hour
6 0
3 years ago
The volume of a gas is 200.0 mL at 275 K and 92.1 kPa. Find its volume at STP.
ycow [4]
To solve this question we will use ideal gas equation:
p*V=n*R*T
Where:
p = pressure
V = volume
n = number of moles
R = gas constant
T = temperature

We can rearrange formula to get:
\frac{p*V}{T} =n*R
We are working woth same gas so we can write following formula. Index 1 stands for conditions before change and index 2 stands for conditions after change.
\frac{ p_{1}*V_{1} }{T_{1}} = \frac{ p_{2}*V_{2} }{T_{2}}

We are given:
p1=92.1kPa = 92100Pa
V1=200mL = 0.2L
T1=275K
p2= 101325Pa
T2=273K
V2=?

We start by rearranging formula for V2. After that we can insert numbers:
{ p_{1}*V_{1} *T_{2}} = { p_{2}*V_{2}*T_{1} } \\  \\ V_{2}= \frac{p_{1}*V_{1} *T_{2}}{ p_{2}*T_{1}}  \\  \\ V_{2}=  \frac{92100*0.2*273}{101325*275}  \\  \\ V_{2}= 0.18L=180mL
7 0
4 years ago
How many windows should the real tree house have
Assoli18 [71]

Answer:

88

Explanation:

3 0
3 years ago
Given that a fluid at 260°F has a kinematic viscosity of 145 mm^2/s, determine its kinematic viscosity in SUS at 260°F.
Oduvanchick [21]

Answer:

kinematic viscosity in SUS is = 671.64 SUS

Explanation:

given data

kinetic viscosity = 145 mm^2/s

we know

1 mm = 0.1 cm

so kinetic viscosity in cm is \nu =145 (0.1)^{2} =1.45 cm^{2}/s

other unit of kinetic viscosity is centistokes

1 cm^{2}/s = 100 cst

so 1.45 cm^2/s will be 145 cst

if the temperature is 260°f , then cst value should be multiplied by 4.632. therefore kinematic viscosity in SUS is = 4.362 *145 = 671.64 SUS

5 0
3 years ago
The momentum of an electron is 1.75 times larger than the value computed non-relativistically. What is the speed of the electron
FrozenT [24]

Answer:

<em>Speed of the electron is 2.46 x 10^8 m/s</em>

<em></em>

Explanation:

momentum of the electron before relativistic effect = M_{0} V

where M_{0} is the rest mass of the electron

V is the velocity of the electron.

under relativistic effect, the mass increases.

under relativistic effect, the new mass M will be

M = M_{0}/ \sqrt{1 - \beta ^{2}  }

where

\beta = V/c

c  is the speed of light = 3 x 10^8 m/s

V is the speed with which the electron travels.

The new momentum will therefore be

==> M_{0}V/ \sqrt{1 - \beta ^{2}  }

It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have

1.75M_{0} V = M_{0}V/ \sqrt{1 - \beta ^{2}  }

the equation reduces to

1.75 = 1/ \sqrt{1 - \beta ^{2}  }

square both sides of the equation, we have

3.0625 = 1/(1 - \beta ^{2} )

3.0625 - 3.0625\beta ^{2} = 1

2.0625 = 3.0625\beta ^{2}

\beta ^{2} = 0.67

β = 0.819

substitute for  \beta = V/c

V/c = 0.819

V = c x 0.819

V = 3 x 10^8 x 0.819 = <em>2.46 x 10^8 m/s</em>

6 0
3 years ago
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