A sample of radioactive waste has a half-live of 40 years and an activity level of 4 curies. After how many years will the activ
1 answer:
After 160 years, the activity level of the sample will be 0.5 curies.
<h3>What is half-life?</h3>Half life of any radioactive waste is the half decay of that product.
The formula is
Where, λ is 4 cruies
λ1 is 0.5 cruies
b = 40 years
Putting the values in the equation
Thus, the correct option is 160 years.
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Answer: hydroxide ions
Explanation:
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According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.
As KOH can give hydroxide ions on dissociation , it is considered as arrhenius base.
Answer:- The Ka for the acid is .
Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:
HA(aq)\rightarrow H^+(aq) + A^-(aq)
Now, we make the ice table for this equation as:
HA(aq)\rightarrow H^+(aq) + A^-(aq)
I 0.25 0 0
C -X +X +X
E (0.25 - X) X X
where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.
X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.
Where, Ka is the acid ionization constant. Let's plug in the values.
Let's calculate the value of X first using the equation:
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on taking antilog ob above equation we get:
= 0.00195
So, X = 0.001195
Let's plug in this value of X in the equation:-
So, the value of Ka for butyric acid is .
Answer:
Volume of water at this temperature is 27.2 mL
Explanation:
We know that
Here density of water is 0.992 g/mL
Here mass of water is 27.0 g
So
=
= 27.2 mL