Answer:
Push and pull both are forces , but the difference is in their direction at which it is applied . If the force applied in the direction of motion of the particle then we call it as push . If that force applied in the direction OPPOSITE to the motion of particle then it is termed as pull
Recall that average velocity is equal to change in position over a given time interval,

so that the <em>x</em>-component of
is

and its <em>y</em>-component is

Solve for
and
, which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.


Note that I'm reading the given details as

so if any of these are incorrect, you should make the appropriate adjustments to the work above.
B: Extension Lines! You could have just searched this up on google
Answer:
The radiation pressure of the light is 3.33 x 10⁻⁶ Pa.
Explanation:
Given;
intensity of light, I = 1 kW/m²
The radiation pressure of light is given as;

I kW = 1000 J/s
The energy flux density = 1000 J/m².s
The speed of light = 3 x 10⁸ m/s
Thus, the radiation pressure of the light is calculated as;

Therefore, the radiation pressure of the light is 3.33 x 10⁻⁶ Pa.