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Setler [38]
3 years ago
12

How many mL of alcohol are in 240 mL of 95.0% alcohol solution?

Chemistry
2 answers:
tino4ka555 [31]3 years ago
5 0
To work it out, you divide 240 by 100 to work out 1% of it, then multiply that by 95 to work out 95% of it. So
(240/100) * 95 = 228mL
Marat540 [252]3 years ago
3 0

Answer:228 mL of alcohol are in 240 mL of 95.0% alcohol solution.

Explanation:

Total volume of the solution = 240 mL

Percentage of alcohol in solution = 95.0%

Volume of volume of alcohol in solution = V

95.0\%=\frac{V}{240 mL}\times 100

V = 228 mL

228 mL of alcohol are in 240 mL of 95.0% alcohol solution.

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Answer: The equilibrium constant for the given reaction is 0.0421.

Explanation:

PCl_5\rightleftharpoons PCl_3+Cl_2

Concentration of [PCl_5] =  0.0095 M

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The expression of the equilibrium constant is given as:

K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}

K_c=0.0421 (An equilibrium constant is an unit less constant)

The equilibrium constant for the given reaction is 0.0421.

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4 years ago
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Answer:

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w-?

m(Mg)=wm
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