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shepuryov [24]
3 years ago
13

A solute and a solvent are mixed together. What requirement would enable you to predict the the substances would form a homogene

ous solution?
Chemistry
2 answers:
Trava [24]3 years ago
8 0
<span>A solute and a solvent are mixed together. In order to say that the substances form a homogeneous solution, it should be that the solute dissolve completely in the solvent that is you would not be able to see solute particles separate from the solvent. Hope this answers the question. Have a nice day.</span>
Tju [1.3M]3 years ago
4 0

Answer: Solution is the answer

Explanation:

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how is the ammonium ion (NH4)1- and the oxalate ion (C2O4) 2- combine written in the ionic compound formed?
lana66690 [7]

Answer: Shown In Photo

Explanation:

just crisscross as shown in photo good luck i suck @ explaining

4 0
3 years ago
If an atom has 104 electrons, 157 neutrons, and 104 protons, what is its approximate atomic mass?
irina1246 [14]
Atomic mass is number of protons + number of neutrons (disregard electrons in mass calculations). 104 + 157 = 261.
8 0
3 years ago
Which of the following are hydrocarbons?
Elden [556K]

Answer:

B or C

Explanation:

I think it's C

8 0
2 years ago
The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude
Vika [28.1K]

Answer:

The answer is "As Q=336, at high-temperature \Delta G_{rxn}>0 and WhenK>1,\Delta G^{\circ}_{rxn}>0."

Explanation:

The equation for the reaction is:

A(g) \leftrightharpoons  B(g)  

K=5.8\\\\Q=336

At equilibrium,

\Delta G^{\circ}_{rxn}>0=-RT \ln \ K

When k=5.8(>1), the value of \ln k would be positive

So, \Delta G^{\circ}_{rxn} is negative (< 0)

So if K > l, \Delta G^{\circ}_{rxn}

If the reaction is not in equilibrium so the equation is :

\Delta G_{rxn}>0=\Delta G^{\circ}_{rxn}+RT \ln Q

Substituting the expression:

\Delta G_{rxn}>0= (-RT \ln K) + RT \ln  Q

                 = RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature \Delta G_{rxn}>0.

5 0
3 years ago
The recommended application for dicyclanil for an adult sheep is 65 mg/kg of body mass. If dicyclanil is supplied in a spray wit
babunello [35]

Answer:

91 millilitres

Explanation:

Recommended application = 65mg / Kg

This means 65 mg of dicyclanil per kg (1 kg of body mass).

Concentration = 50 mg / mL

How many millilitres required to treat 70kg adult?

If 65mg = 1 kg

x = 70 mg

x = 70 * 65 = 4550 mg

Concentration = Mass / Volume

50 mg/mL = 4550 / volume

volume = 4550 / 50 = 91 mL

8 0
3 years ago
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