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Paraphin [41]
3 years ago
6

13. Which of the following correctly provides the names and formulas of polyatomic ions?

Chemistry
1 answer:
sukhopar [10]3 years ago
4 0
Mirror no :HCO3
Answer HCO3
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Which phrase related to electromagnetism applies only to electric force? A. Attraction and repulsion B. North and south C. Push
iogann1982 [59]

Answer:

positive and negative

Explanation:

ik its prob not helpful now but ye sorry no ones answered lol

3 0
1 year ago
5. You are investigating an arson scene and you find a corpse in the rubble, but you suspect that the victim did not die as a re
Marina CMI [18]

Answer:

See the answer below.

Explanation:

Fire has three major components:

  • Heat
  • Smoke
  • Gases ( in form of CO, CO2 etc)

If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.

If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.

<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>

8 0
2 years ago
A 1.2 m aqueous solution of an ionic compound with the formula MX2 has a boiling point of 101.4 celsisus. Calulate the van't Hof
Olegator [25]
The boiling point increase of a solution is a colligative property, which means that it is related with the solvent and the concentration of the solute, as per this formula:

ΔT = i * kb * m

Where, ΔT is the increase in the boiling point, i is the van't Hoof factor (which accounts for the numberof particles that are dissolved), kb is the boiling point and m the molality of the solution.

Gvien the normal boiling point of 100°C for pure water, ΔT = 101.4 °C - 100.0 °C = 1.4 °C.

Kb = 0.512 °C / m

m = 1.2 m

Therefore, i = ΔT / (kb * m) = 1.4°C / (0.512 °C/m * 1.2m) = 2.28

Answer: 2.28
5 0
3 years ago
How to first ionization energies vary within groups and across periods
trapecia [35]

Answer:

Ionisation energy increases along a period but decreases down a group

Explanation:

As you go along the period, the amount of protons in the nuclear increases. This causes nuclear attraction to increase meaning the attraction between the protons and the electrons is higher. This causes the electrons to be held more tightly to the nucleus meaning they are harder to remove. As well as that, the shielding stays the same along a period since the electrons are being added to the same shell, just different orbitals. Overall this makes it harder to remove an electron as you go along a period causing the ionisation energy to increase along a period.

On the other hand when you go down a group, the atomic radius increases. This is because the electrons are added to new shells which are further away from the nucleus, this also causes shielding to increase as there are more shells. This means the outer electrons being removed are held less tightly by the protons in the nucleus meaning they are easier to remove. This means that the ionisation energy decrease down a group.

8 0
2 years ago
Answer whats on the image PLEASE
kondaur [170]

Answer:

1.97201398 g

Explanation:

Multiply the theoretical yield by the percent yield. Don't forget to move the decimal over 2 on the percent before multiplying or to use the percent button on your calculator.

7 0
2 years ago
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