Answer:
The wavelength of the wave is 2.34 nm.
Explanation:
It is required to find the wavelength of a
wave. A wave moves with a speed of light. Speed of a wave is given in terms of wavelength and frequency. So,


So, the wavelength of the wave is 2.34 nm.
<span>The angular momentum of a particle in orbit is
l = m v r
Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2"
m_1 v_1 r_1 = m_2 v_2 r_2
Assuming that the mass did not change, conservation of angular momentum demands that
v_1 r_1 = v_2 r_2
or
v1 = v_2 (r_2/r_1)
Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have
v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s
Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
Answer:
a) 256 ft
b) 32 ft/s
c) -32 ft/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²

Maximum height = 256 ft
When s = 240 ft

Speed of the ball at 240 ft is 32 ft/s while going up
Now this will be the velocity of the ball when it reaches 240 ft, which will be considered as the initial velocity

Now, initial velocity will be considered as zero

Speed of the ball at 240 ft is -32 ft/s while going down
<span>a. less biomass
b. more biomass
c. more broad-leaf trees
d. locations near the equator
i would say c
</span>
Answer:
393.6m/s
Explanation:
Given parameters:
Acceleration = 8.5m/s²
Distance = 300m
Final velocity = 400m/s
Unknown:
Initial velocity = ?
Solution:
To solve this problem, we use the expression below;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
So;
v² - 2as = u²
u² = v² - 2as
u² = 400² - (2 x 8.5 x 300)
u = 393.6m/s