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frutty [35]
3 years ago
12

How does food in a fridge cool down​

Chemistry
2 answers:
Dovator [93]3 years ago
7 0
Convection occurs through the use of refrigerant gases and a compressor
Nimfa-mama [501]3 years ago
6 0

Answer:

Convection occurs through the use of refrigerant gases and a compressor

Explanation:

x

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I just need 4-8! Plz hurry!!!!!!!!!!!
RSB [31]

Answer:

4: 90N

5: 7.77777m/s

6: 4

7: 12.5609756098

8: 187.5

Explanation:

8 0
3 years ago
Water has a density of 1g/ml. what is the mass of the water if it fills a 10ml container?
notka56 [123]
It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
8 0
3 years ago
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Given the equation representing a system at equilibrium in a sealed, rigid container:
LenaWriter [7]

Answer:

Choice 1. "HI to increase".

Explanation:

I found out the hard way.

4 0
3 years ago
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What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl
Kitty [74]

Answer:

\large \boxed{\text{0.012 mol}}  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL:                    70.

c/mol·L⁻¹:             0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }

3 0
3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
4 years ago
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