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GuDViN [60]
2 years ago
10

in an aerosol spray can with a volume of 456 ml contains is 3.18g of propane gas as a propellant If the can is at 23° C and 50 A

TM what volume will be the propane occupy at STP
Chemistry
1 answer:
Mekhanik [1.2K]2 years ago
8 0

Answer:    Answer:

21.03L

Explanation:

V1 = 456mL = 0.456L

T1 = 23°C = (23 + 273.15)K = 296.15K

P1 = 50atm

V2 = ?

T2 = 273.15K

P2 = 1.0atm

Note : P2 and T2 are at STP which are 1.0atm and 273.15K

To find V2, we have to use the combined gas equation,

(P1 × V1) / T1 = (P2 × V2) / T2

P1 × V1 × T2 = P2 × V2 × T1

V2 = (P1 × V1 × T2) / (P2 × T1)

V2 = (50 × 0.456 × 273.15) / (1.0 × 296.15)

V2 = 6227.82 / 296.15

V2 = 21.029L

Final volume of the gas is 21.03L

Explanation:

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3 years ago
4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the mate
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Q = m* c*ΔT ,

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Plugging value in heat formula :

4720 KJ = m * 2730 \frac{J}{Kg * K} * 65 K

4720 KJ = m * 177450 \frac{J}{Kg}

[[Converting 177450 \frac{J}{Kg}  to \frac{KJ}{Kg}

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Dividing both side by 177.450 \frac{KJ}{Kg}

\frac{4720 KJ}{177.450 \frac{KJ}{Kg}}  = m * \frac{177.450\frac{KJ}{Kg} }{177.450\frac{KJ}{Kg} }

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6 0
3 years ago
A 48.9 g piece of aluminum is dropped in a graduated cylinder partially filled with water. The original volume of water in the c
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Explanation:

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To find the mass in 1mL we need to determine the volume that the piece occupies:

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Explanation:

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